Answer:
4 km/hr
Explanation:
The computation of the actual velocity is shown below:
Because the path of its paddles is opposed to the current direction, the real velocity can be determined by deducting the current velocity to its velocity while paddling
So, the actual velocity is
= Upstream - downstream
= 19 km/hr - 15 km/hr
= 4 km/hr
As we can see it is in positive, so it is an upstream direction
Answer:
a) 1450watts
b) 564watts
c) 1.11
Explanation:
Power consumed = IV
I is the current rating
V is the operating voltage
If a blow-dryer and a vacuum cleaner each operate with a voltage of 120 V and the current rating of the blow-dryer is 12 A, while that of the vacuum cleaner is 4.7 A then their individual power rating is calculated thus;
a) For blow-dryer
Operating voltage = 120V
Its current rating = 12A
Power consumed = IV
= 120×12
= 1440watts
b) For vacuum cleaner:
Operating voltage is the same as that of blow dryer = 120V
Its current rating = 4.7A
Power consumed = IV
= 120×4.7
= 564watts
c) Energy used = Power consumed × time taken
Energy used = Power × time
Energy used by blow dryer = 1440×20×60
= 1,728,000Joules
Energy used up by vacuum cleaner = 564×46×60
= 564×2760
= 1,556,640Joules
Ratio of the energy used by the blow-dryer in 20 minutes to the energy used by the vacuum cleaner in 46 minutes will be 1,728,000/1,556,640 = 1.11
C because it’s not a or B so 50/50 c or d and d is def not the answer so c
Answer:
Explanation:
You can always figure out something to say about a question like this if you have a formula to work with. Likely you do.
There are many ways it can be written
R = k * L / A
So here's the answer.
Resistance = k which depends of the properties of the material used to make the wire * the Length of the wire divided by the cross sectional area of the wire.
Answer:
Current through the surface at t = 1.1 s is 21.37 A.
Explanation:
The charge is passing through a surface of area varies with time as :
Here,
t is in seconds
The rate of change of electric charge is called electric current. It is given by :
At t = 1.1 s, Current,
So, the instantaneous current through the surface at t = 1.1 s is 21.37 A.
