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3 years ago

13

It is known that a shark can travel at a speed of 15 m/s.how far can a shark go in 10 seconds?

2 answers:

MrRissso [65]3 years ago

8 0

If a shark can travel 15 miles per second, then it can go 150 miles in 10 seconds.

Alla [95]3 years ago

6 0

Start with 15 m/s. There are 2 units and you need to cancel the seconds to get meters.

10 seconds has seconds as a unit. This can be used to cancel the sec in the denominator of 15 m/s. This just a little tip I use when I'm unsure about what to do.

15 m/s x 10 s = 150 meters

Hope I helped :)

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Explanation:

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2 years ago

In a tank full of water, the pressure on a surface 2 meters below the water level is 1.5 kPA. What's the pressure on a surface 6

Lina20 [59]

Answer:

P = 40.7kPa

Explanation:

To find the pressure on a surface 6 meter below you use the following formula, which takes into account the heights in which pressures are measured and also the density of the fluid and the gravitational acceleration:

$P_2-P_1=-\rho g(y_2-y_1)$ (1)

P2: pressure for a height of -6 m = ?

P1: pressure for a height of -2 m = 1.5kPa = 1500 Pa

ρ: density of water = 1000kg/m^3

g: gravitational acceleration = 9.8 ms^2

y2: -6m

y1: -2m

(the height is measure from the water level, because of that, the heights are negative)

You solve the equation (1) for P1:

$P_1=P_2-\rho g(y_2-y_1)$ (2)

Next, you replace the values of all variables in equation (2):

$P_2=1500Pa-(1000kg/m^3)(9.8m/s^2)(-6-(-2))m=40700Pa\\\\P_2=40.7kPa$

hence, the pressure on a surface 6 m below the water level is 40.7kPa

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2 years ago

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2 years ago

How many grams of NaCl is required to saturate a solution at 90°C?

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2 years ago

How much heat is released upon converting one mole of steam (18.0

Anika [276]

4.65 × 10⁴ Joules of heat is released upon converting one mole of steam to water.

$\texttt{ }$

<h3>Further explanation</h3>

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

$\large {\boxed{Q = m \times c \times \Delta t} }$

<em>Q = Energy ( Joule )</em>

<em>m = Mass ( kg ) </em>

<em>c = Specific Heat Capacity ( J / kg°C ) </em>

<em>Δt = Change In Temperature ( °C )</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

initial temperature of steam = t = 100.0°C

specific heat capacity of water = c = 4.186 J/gK

mass of steam = m = 18.0 gram

final temperature of water = t' = 25.0°C

specific latent heat of vaporization of water = Lv = 2268 J/g

<u>Asked:</u>

heat released = Q = ?

<u>Solution:</u>

$\boxed {\large {\texttt{steam 100}^oC \overset{[Q_1]}{\rightarrow} \texttt{water 100}^oC \overset{[Q_2]}{\rightarrow} \texttt{water 25}^oC}}$

$Q = Q_1 + Q_2$

$Q = mL_v + mc\Delta t$

$Q = 18.0(2268) + 18.0(4.186)(100-25)$

$Q = 40824 + 5651.1$

$Q = 46475.1 \texttt{ Joules}$

$Q \approx 4.65 \times 10^4 \texttt{ Joules}$

$\texttt{ }$

<h3>Learn more</h3>

Efficiency of Engine : brainly.com/question/5597682
Flow of Heat : brainly.com/question/3010079
Difference Between Temperature and Heat : brainly.com/question/3821712

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<h3>Answer details </h3>

Grade: College

Subject: Physics

Chapter: Thermal Physics

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Keywords: Heat , Temperature , Block , Aluminium , Ice , Cold , Water

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2 years ago

Read 2 more answers