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adell [148]
2 years ago
15

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive allele in humans. A woman whose father

suffered from G6PD marries a man who has the disease. What proportion of their sons would have the disease? (A) 100 % (B) 1 / 2 (C) 1 / 4 (D) zero
Biology
1 answer:
Goryan [66]2 years ago
7 0

The proportion of their sons having the disease would be <u>zero.</u>

The 46 chromosomes found in human cells could be divided into two groups: autosomes (44) as well as sex chromosomes (2). In contrast to bacterial chromosomes, human chromosomes are typically linear. Such as bacteria, they could be housed inside the nucleus.

Let's refer to the dominant gene as XG as well as the mutant allele as Xg due to the X-linked recessive characteristic. The woman most likely possesses the genotype XG/Xg, having Xg coming from her father as well as XG from just a healthy mother.

The husband would belong to the genotype Xg/Y should he have a G6PD deficiency. A Punnett square can be utilized to estimate the genotypes of offspring due to our being aware of the parental genotypes.

This would not change the estimated percentage of sons who will be affected because the father sometimes doesn't pass on his X chromosome to their sons.

To learn more about disease here

brainly.com/question/14016921

#SPJ4

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