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Shtirlitz [24]
2 years ago
11

Using data in Appendix A ,calculate the number of atoms in 1 tonne of iron

Engineering
1 answer:
maksim [4K]2 years ago
4 0
<h2>Answer:</h2>

1.0783*10^{28}(atoms).

<h2>Explanation:</h2>

<em>Since I don't have access to "Appendix A", I'll solve the problem using data from the periodic table.</em>

<em />

<h3>1. Determine the molar mass of iron.</h3>

<em>According to the periodic table, the molar mass of iron is:</em>

55.845g/mole.

<h3>2. Convert 1 tonne to grams.</h3>

1(tonne)*1000=1000kg\\1000kg*1000=1000000g=10^6g

<h3>3. Apply rule of 3.</h3>

55.845g ----------- 1 mole

10^6g ----------- x

x=\frac{10^6*1}{55.845}=17906.7061(moles)

<h3>4. Determine the amount of atoms.</h3>

<em>Considering that there are, approximately, </em>6.022*10^{23} atoms in a mole of any element, apply another rule of 3.

1 mole --------------------- 6.022*10^{23}(atoms)

17906.7061(moles) --------------------- x

x=\frac{17906.7061*6.022*10^{23}}{1}=1.0783*10^{28}.

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Write a function which multiplies the values in odd position values by 10. Odd positions in this case refers to the first value
xxMikexx [17]

Answer:

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Explanation:

#include<iostream>

#include<cstdlib>

using namespace std;

//structure of linked list

struct linkedList

{

  int data;

  struct linkedList *next;

};

//print linked list

void printList(struct linkedList *head)

{

  linkedList *t=head;

 

  while(t!=NULL)

  {

      cout<<t->data;

      if(t->next!=NULL)

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}

//insert newnode at head of linked List

struct linkedList* insert(struct linkedList *head,int data)

{

  linkedList *newnode=new linkedList;

  newnode->data=data;

  newnode->next=NULL;

 

  if(head==NULL)

  head=newnode;

  else

  {

      struct linkedList *temp=head;

      while(temp->next!=NULL)

      temp=temp->next;

     

      temp->next=newnode;

     

      }

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void multiplyOddPosition(struct linkedList *head)

{

  struct linkedList *temp=head;

  while(temp!=NULL)

  {

      temp->data = temp->data*10; //multiply values at odd position by 10

      temp = temp->next;

      //skip odd position values

      if(temp!= NULL)

      temp = temp->next;

  }

}

int main()

{

  int n,data;

  linkedList *head=NULL;

 

// create linked list

  head=insert(head,20);

  head=insert(head,5);

  head=insert(head,11);

  head=insert(head,17);

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  head=insert(head,4);

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  cout<<"\nLinked List : ";

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  multiplyOddPosition(head);

  cout<<"\nLinked List After Multiply by 10 at odd position : ";

  printList(head); //print list

 

  return 0;

}

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