Ask question

Ask question

All categories

3 years ago

9

Beginning in the 1960s, various advocates of the design-build model began to agitate against the design-bid-build approach and f

or a change,
O False
O True

1 answer:

shutvik [7]3 years ago

8 0

It will be True hope this helps!!

You might be interested in

The heat flux through a 1-mm thick layer of skin is 1.05 x 104 W/m2. The temperature at the inside surface is 37°C and the tempe

miss Akunina [59]

Answer:

a) Thermal conductivity of skin: $k_{skin}=1.5W/mK$

b) Temperature of interface: $T_{interface}=35.6\°C$

Heat flux through skin: $\frac{Q}{A}=2100W/m^2$

Explanation:

a)

$k=\frac{QL}{A(T_{2}-T_{1})}$

Where: $k$ is thermal conductivity of a material, $\frac{Q}{A}$ is heat flux through a material, $L$ is the thickness of the material, $T_{1}$ is the temperature on the first side and $T_{2}$ is the temperature on the second side

$k_{skin}=\frac{QL}{A(T_{2}-T_{1})}$

$k_{skin}=\frac{Q}{A}*\frac{L}{(T_{2}-T_{1})}$

$k_{skin}=1.05*10^{4}*\frac{1*10^{-3}}{(37-30)}$

$k_{skin}=1.5W/mK$

b)

$k_{insulation}=\frac{k_{skin}}{2}$

$k_{insulation}=\frac{1.5}{2}$

$k_{insulation}=0.75W/mK$

The heat flux between both surfaces is constant, assuming the temperature is maintained at each surface.

$\frac{Q}{A}=\frac{k(T_{2}-T_{1})}{L}$

$\frac{k_{skin}(T_{skin}-T_{interface})}{L_{skin}}=\frac{k_{insulation}(T_{interface}-T_{insulation})}{L_{insulation}}$

$\frac{1.5*(37-T_{interface})}{0.001}=\frac{0.75*(T_{interface}-30)}{0.002}$

$55500-1500T_{interface}=375T_{interface}-11250$

$1875T_{interface}=66750$

$T_{interface}=35.6\°C$

$\frac{Q}{A}=\frac{k_{skin}(T_{skin}-T_{interface})}{L_{skin}}$

$\frac{Q}{A}=\frac{1.5*(37-35.6)}{0.001}$

$\frac{Q}{A}=2100W/m^2$

3 0

3 years ago

Multiple Choice

hichkok12 [17]

Answer:

Geological engineers can help determine if the soil and structural stability in the building's location are satisfactory.

Explanation:

Geologic Engineering refers to a job which applies<em> geology to engineering</em>. This type of job focuses on the investigation of sites in response to<em> soil, rock </em>and <em>groundwater.</em> They help design the major structures for engineering works, thus, it is also their role <u><em>to know whether the building's soil and structural stability are satisfactory.</em></u> They determine <em>how much of the structure is a safe load for the soil it is standing upon.</em> They also test the strength of both rock and soil at different depths. This will help them know whether the location will be suitable for the skyscraper.

4 0

3 years ago

A single phase, 50-KVA, 2400-240-volt, 60 Hz distribution transformer has the following parameters: •

never [62]

Answer:

B) voltage at the sending end of the feeder = 2483.66 v

Explanation:

attached below is the the equivalent circuits and the remaining solution for option A

B) voltage = 2400 v

I = $\frac{50*10^3}{2400}$ = 20.83 A

calculate voltage at sending end ( Vs )

Vs = 2400 + 20.83 ∠ -cos^-1 (0.8) ( 0.75*2 + 0.5 + j 2 + j2 )

hence Vs = 2483.66 ∠ 0.961

therefore voltage at the sending end = 2483.66 v

8 0

4 years ago

Admission to an aquarium is $14 per person. There is also an IMAX theatre in the building, which charges $8 per ticket for a 3D

adoni [48]

Answer:

x=14a+8b+16.5c

Explanation:

x=total cost

a=number of people in just aquarium

b=number of people in just IMAX

c=number of people in both

c=(14+8)×0.75=22×0.75=16.5

8 0

3 years ago

Three masses are attached to a uniform meter stick, as shown in Figure 12.9. The mass of the meter

sp2606 [1]

At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero

The mass of that balances the system is $\underline {316.\overline 6}$ kg

The normal reaction force at the fulcrum is <u>5,804.25 N</u>

Rason:

The mass of the stick = 150.0 g

Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂

Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum

Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum

Required:

To find the mass of m₃

Solution:

Taking moment about the fulcrum, we have;

50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30

9,500 = m₃×30

$m_3 = \dfrac{9,500}{30} = 316. \overline 6$

The mass of that balances the system when it is attached at the right end of the stick, m₃ = $316.\overline 6$ kg

Normal reaction at the fulcrum = (50 + 75 + 150 + $316.\overline 6$ ) × 9.81 = 5804.25

The normal reaction at the fulcrum is 5,804.25 N

Learn more about the moment of a force here:

brainly.com/question/19464450

8 0

2 years ago