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Novosadov [1.4K]
3 years ago
15

Describe the cycle that purifies drinking water. 40 points

Engineering
2 answers:
vovikov84 [41]3 years ago
8 0

Answer:

4 po

Explanation:

Sunny_sXe [5.5K]3 years ago
5 0
Umm the Water cycle sorry I’m trying
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Wastewater flows into a once it is released into A floor drain
Phoenix [80]

Answer: C) Sump pit

Explanation:

Wastewater from the house is allowed to flow out of places such as the bathroom or the kitchen sink through a floor drain.

This floor drain is connected to a sump pit which is typically located at the lowest point in the house (lowest point in basement) so that water can flow into it easier.

When the wastewater is released from the floor drain, it will flow into the sump pit. This water is in turn removed from the pit by a sump pump.

8 0
3 years ago
A 3-phase , 1MVA, 13.8kV/4160V, 60 Hz, transformer with Y-Delta winding connection is supplying a3-phase, 0.75 p.u. load on the
Tanya [424]

Answer:

a) 23.89 < -25.84 Ω

b) 31.38 < 25.84 A

c) 0.9323 leading

Explanation:

A) Calculate the load Impedance

current on load side = 0.75 p.u

power factor angle = 25.84

I_{load} = 0.75 < 25.84°

attached below is the remaining part of the solution

<u>B) Find the input current on the primary side in real units </u>

load current in primary = 31.38 < 25.84 A

<u>C) find the input power factor </u>

power factor = 0.9323 leading

<em></em>

<em>attached below is the detailed solution </em>

8 0
3 years ago
Two gage marks are placed exactly 250 mm apart on a 12-mm-diameter aluminum rod with E 5 73 GPa and an ultimate strength of 140
NNADVOKAT [17]

Answer:

81.76 N/mm² ( MPa), 1.71233

Explanation:

Modulus of elasticity = stress / strain

stress = modulus of elastic × strain

strain = ΔL / L = 250.28 mm - 250 mm / 250 mm = 0.00112

Modulus of elasticity E = 73 GPa = 73 × 10³ MPa where 1 MPa = 1 N/mm²

E = 73 × 10³N/mm²

stress =  73 × 10³N/mm²× 0.00112 = 81.76 N/mm² ( MPa)

b) Factor of safety = maximum allowable stress / induced stress = 140 MPa / 81.76 MPa = 1.71233

8 0
4 years ago
Match the benefit of full synthetic oil with engine conditions: All engines
mart [117]

Answer:

1. All engines  exhibit wear over time ⇒ <em>Synthetic Improves engine protection by resisting oil breakdown.</em>

Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.

2. Engines are cold at start-up and not while running ⇒ <em> Synthetic provides maximum protection in extreme hot and cold temperature conditions.</em>

By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.

3.  If oil is thicker, engines lose power and efficiency ⇒ <em>Synthetic has greater resistance to oil thickening to maintain engine efficiency.</em>

Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.

7 0
3 years ago
Consider a cubic crystal with the lattice constant a. Complete the parts (a)-(c) below. (a) Sketch the crystallographic planes w
Anna [14]

Answer:

(a) See attachment

(b) The two planes are parallel because the intercepts for plane [220] are X = 0,5 and Y = 0,5 and for plane [110] are X = 1 and Y = 1. When the planes are drawn, they keep the same slope in a 2D plane.

(c) d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

Explanation:

(a) To determine the intercepts for an specific set of Miller indices, the reciprocal intercepts are taken as follows:

For [110]

X = \frac{1}{1} = 1; Y = \frac{1}{1} = 1; Z = \frac{1}{0} = \inf.

For [220]

X = \frac{1}{2} = 0,5;Y = \frac{1}{2} = 0,5;Z = \frac{1}{0} = \inf.

The drawn of the planes is shown in the attachments.

(b) Considering the planes as two sets of 2D straight lines with no intersection to Z axis, then the slope for these two sets are:

For (1,1):

K_1 = \frac{1}{1} = 1

For (0.5, 0.5):

K_2 = \frac{0.5}{0.5} = 1

As shown above, the slopes are exactly equal, then, the two straight lines are considered parallel and for instance, the two planes are parallel also.

(c) To calculate the d-spacing between these two planes, the distance is calculated as follows:

The Miller indices are already given in the statement. Then, the distance is:

\frac{1}{d^{2}} = \frac{h^{2} + k^{2} + l^{2}}{a^{2}}

d = \frac{a}{\sqrt{h^{2} + k^{2} + l^{2}}} = \frac{1}{\sqrt{2}} =   0,707

7 0
3 years ago
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