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Vlad1618 [11]
3 years ago
12

What is the weight density of a 2.24 in diameter titanium sphere that weights 0.82 lb?

Engineering
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

0.14\ lb/in^{3}

Explanation:

Density is defined as mass ler unit volume, expressed as

\rho=\frac {m}{v}

Where m is mass, \rho is density and v is the volume. For a sphere, volume is given as

v=\frac {4\pi r^{3}}{3}

Replacing this into the formula of density then

\rho=\frac {m}{\frac {4\pi r^{3}}{3}}

Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then

\rho=\frac {0.82}{\frac {4\pi 1.12^{3}}{3}}=0.13932044952427\approx 0.14 lb/in^{3}

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stellarik [79]

Answer:

Explanation:

Given

velocity at A is v=4\ ft/s

For r=500\ ft

velocity is increasing at \dot{v}=0.004t\ ft/s^2

Tangential acceleration is given by

a_t=\frac{\mathrm{d} v}{\mathrm{d} t}

a_t=0.004t=\frac{\mathrm{d} v}{\mathrm{d} t}

\int 0.004tdt=\int dv

\int dv=\int 0.004tdt

v=0.002t^2+c

at t=0\ v=4\ ft/s

4=0.002\cdot 0+c

c=4\ ft/s

thus v=0.002t^2+4

Velocity in terms of Displacement is given by

v=\frac{\mathrm{d} s}{\mathrm{d} t}

\Rightarrow \int ds=\int \left ( 0.002t^2+4\right )dt

\Rightarrow s=\frac{0.002t^3}{3}+4t

When car has traveled \frac{3}{4} th of distance i.e.

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s=750\pi

750\pi =\frac{0.002t^3}{3}+4t

\Rightarrow \frac{0.002t^3}{3}+4t-2356.5=0

on solving we get t=139.23\ s

Thus velocity at t=139.23\ s

v=42.76\ s

(b)Acceleration when car has traveled three-fourth the way of track

normal acceleration a_n=\frac{v^2}{r}=\frac{(42.76)^2}{500}

a_n=3.658\ m/s^2

Tangential acceleration a_t at t=139.23\ s

a_t=0.556\ m/s^2

Net acceleration a_t=\sqrt{(a_n)^2+(a_t)^2}

a_n=\sqrt{(3.658)^2+(0.556)^2}

a_n=3.7\ m/s^2

   

8 0
3 years ago
The efficiency of a steam power plant can beincreased by bleeding off some of the steam thatwould normally enter the turbine and
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Answer:

Explanation:

This is Answer....

5 0
2 years ago
The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bendin
Degger [83]

Answer:

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

             αbend,p = 19.648 ksi ( tensile )

Explanation:

αaxial, p = \frac{-p}{A}   equation 1

αbend, p = \frac{(P*A)*\frac{d}{2} }{I_{z} } equation 2

P = load = 35 kips

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d = column cross section depth = 9.5 in

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equation 2 becomes

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7 0
3 years ago
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Answer:

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Explanation:

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mixer [17]

Answer:

Option D

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Explanation:

Color is one of the physical properties of minerals. Many minerals have a wide range of colors but there are some minerals with one consistent color and such minerals are referred as monochromatic minerals for example azurite. Normally, the streak color tends to be less variable than the color of the whole mineral and impurities or minor chemical components in a mineral react and often control the display color of resultant mineral. Option D is incorrect since mineral's color don't reflect wavelengths of light absorbed by such minerals.

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3 years ago
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