This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally. Here, we are given the new volume of the gas after cooling, and we want to determine to what temperature the gas was cooled.
To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for T2, which we can obtain by rearranging the equation into T2 = V2T1/V1. Given V1 = 130 L, T1 = 250 °C (523.15 K), and V2 = 85 L:
T2 = (85 L)(523.15 K)/(130 L) = 342 K or 68.9 °C. If sig figs are to be considered, since all the values in the question are given to two sig figs, the answer to two sig figs would be either 340 K or 69 °C.
The answer is it changes the texture (shape and size) of the grains.
<u>Explanation</u>:
- During changeability, the protolith experiences changes in the texture of the stone and the mineral make up of the stone. These progressions happen because of the progressions brought about by physical or substance conditions, which for the most part happen in the strong state.
- Because of these progressions, rocks experience changes in temperature and pressure and might be exposed to the differential pressure and aqueous liquids. It likewise happens because of the strength of certain minerals just under specific conditions. These progressions bring about causing the substance responses which may prompt change fit as a fiddle and size.
Answer:
<em>The empirical formula is Ag2O.</em>
<em>The empirical formula is Ag2O.Explanation:</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.</em>
<em>The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to </em><em>2</em><em>O.</em>
<em>do</em><em> </em><em>the</em><em> </em><em>steps</em><em> </em><em>.</em><em>.</em><em>.</em>
To get this into an integer ratio, we divide both numbers by the smaller value.
From this point on, I like to summarize the calculations in a table.
ElementAgMass/gXMolesXllRatiomllIntegers
mAgXXXm7.96Xm0.07377Xll2.00mmm2
mlOXXXXl0.59mm0.0369Xml1mmmml1
There are 2 mol of Ag for 1 mol of O.
Answer:
Kindly check the explanation section.
Explanation:
From the description given in the question above, that is '' H subscript f to the power of degree of the reaction" we have that the description matches what is known as the heat of formation of the reaction, ∆fH° where the 'f' is a subscript.
In order to determine the heat of formation of any of the species in the reaction, the heat of formation of the other species must be known and the value for the heat of reaction, ∆H(rxn) must also be known. Thus, heat of formation can be calculated by using the formula below;
∆H(rxn) = ∆fH°( products) - ∆fH°(reactants).
That is the heat of formation of products minus the heat of formation of the reaction g specie(s).
Say heat of formation for the species is known as N(g) = 472.435kj/mol, O(g) = 0kj/mol and NO = unknown, ∆H°(rxn) = −382.185 kj/mol.
−382.185 = x - 472.435kj/mol = 90.25 kJ/mol
Answer:
Supersaturated solutions
Explanation:
These are the solution which contain more solute than its ability at high temperature.
They comtain more solute concentration than at the normal conditions.