a)Exothermic
b) it goes up
c) The piston must move out
d)The energy is released by the system
e)ΔE = -616 kJ
Explanation:
sign convention for heat flow:
if the heat flows into the system it is marked with positive sign
when the heat flows out the system it is marked with negative sign
sign convention for work
if work is done on the system it is marked positive
if work is done by the system it is marked negative
sign convention for internal energy
if energy absorbed by system mark positive
if energy released by system mark negative
a)
the heat flow flowing out of the system (q= -300 kJ)
thus the reaction is Exothermic
b)
In exothermic reaction, heat flows from the system to surroundings.
surrounding here is water bath.
As the system is exothermic, hence the temperature of water bath goes up
c)
It is given that 316 kJ of work is done by the system, applying expansion.
To maintain constant pressure of 1 atm the decreased pressure can be compensated with an increase on volume . To increase volume the piston must move out
d)
According to 1st law of thermodynamics,
ΔE =q +w ⇒1
here,
ΔE = q +w
ΔE = -300 kJ -316 kJ
ΔE = -616 kJ ⇒2
the negative sign denotes the energy is released by the system
e)
from ΔE = -616 kJ the amount of energy released by the reaction is ΔE = -616kJ
