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kotegsom [21]
2 years ago
6

HELP ASAP 35 POINTS

Mathematics
1 answer:
IgorLugansk [536]2 years ago
3 0

By finding the distance between each pair of consecutive vertices, we could find that the perimeter is 26.8

<h3>How to find the perimeter of the figure?</h3>

To find the perimeter, we need to find the length of each side of the figure in the image.

And remember that the distance between two points (a, b) and (c, d) is:

√( (a - c)^2 + (b - d)^2 )

So we need to find the distance between each of the vertices of the figure.

The first two are (0, 3) and (4, -1). The distance between these is:

d = √( (0 - 4)^2 + (3 + 1)^2 ) = √25 = 5

The second pair is (4, -5) and (4, -1). The distance between these is:

d = √( (4 - 4)^2 + (-5 + 1)^2 ) = √16 = 4

The third pair is (4, -5) and (-5, 4). The distance between these is:

d = √( (4 + 5)^2 + (-5 - 4)^2 ) = √162 = 12.7

The last pair is (-5, 4) and (0, 3), this time the distance is:

d = √( (-5 - 0)^2 + (4 - 3)^2 ) = √26 = 5.1

The perimeter is the sum of these distances:

5 + 4 + 12.7 + 5.1 = 26.8

By finding the distance between each pair of consecutive vertices, we could find that the perimeter is 26.8

If you want to learn more about perimeters:

brainly.com/question/24571594

#SPJ1

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snow_tiger [21]

Answer:

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Step-by-step explanation:

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3 years ago
Find the greatest common factor of the following monomials: 20a3 and 8a2
dimulka [17.4K]

GCF of given monomials are 4a^2

<em><u>Solution:</u></em>

<em><u>Given that we have to find the greatest common factor</u></em>

Given monomials are:

20a^3 \text{ and } 8a^2

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor

Let us first find the GCF of 20 and 8 and then find GCF of variables and then multiply them together

<em><u>GCF of 20 and 8:</u></em>

The factors of 8 are: 1, 2, 4, 8

The factors of 20 are: 1, 2, 4, 5, 10, 20

Then the greatest common factor is 4

GCF\ of\ a^3 \text{ and } a^2\\\\a^3 = a^2 \times a\\\\a^2 = a^2

Thus GCF is a^2

<em><u>Therefore GCF of monomials are:</u></em>

\text{GCF of } 20a^3 \text{ and } 8a^2 = 4 \times a^2 = 4a^2

Thus GCF of given monomials are 4a^2

5 0
3 years ago
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Step-by-step explanation:

we know that

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sin(47\°)=\frac{US}{7.2}

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Answer:

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