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Firdavs [7]
1 year ago
12

What medal has the highest volume?

Chemistry
1 answer:
Afina-wow [57]1 year ago
3 0

The Medal of Honor is the best navy decoration and highest volume.

The President of the USA The Victoria go is the holy grail for Medal of Honor creditors because there are the best in lifestyles. Bearing the inscription For valor and called a VC, this medal turned into first offered for conspicuous bravery' in 1856 and later backdated to the Crimean conflict of 1854. The outstanding service pass is the second maximum army ornament that may be provided to a member of the American military, for intense gallantry and risk of lifestyle in actual combat with an armed enemy force.

The Bronze Star Medal dates lower back to world battle II. these days, it is the fourth-maximum ranking award a provider member can obtain for a heroic and meritorious deed performed in an armed battle. For individuals who acquire the BSM, it's far a sign of their sacrifice, bravery, and honor at the same time as serving their us of a

Learn more about medals here:-brainly.com/question/17634999

#SPJ9

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The magnetic field !
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Born and Meyer developed a quantitative theory of bonding in ionic crystals in which the potential energy of the system is given
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E = NA/R^n - N alpha e^2/ (4 piEoR')

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Where N = number of positive ion pairs

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When This Occurs, Particles Spread Out
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Un tecnico di laboratorio deve preparare una soluzione di carbonato di sodio decaidrato, Na2CO3⋅ 10 H2O per eseguire alcune anal
fiasKO [112]

Answer:

1.  3.70 g Na₂CO₃·10H₂O

2. 50.0 mL of the first solution

Explanation:

1. Prepare the solution

(a) Calculate the molar mass of Na₂CO₃·10H₂O

\begin{array}{rrr}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 2\times22.99 & 45.98\\\text{1C} & 1\times 12.01 & 12.01\\\text{13O}&13 \times16.00 & 208.00\\\text{20H}&20 \times 1.008 & 20.16\\&\text{TOTAL =} & \mathbf{286.15}\\\end{array}

The molar mass of Na₂CO₃·10H₂O is 286.15 g/mol.

(b) Calculate the moles of Na₂CO₃·10H₂O

\text{Moles of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\= \text{0.250 L solution} \times \dfrac{\text{0.0500 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 L solution}}\\\\= \text{0.0125 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

(c) Calculate the mass of Na₂CO₃·10H₂O

\text{Mass of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O }\\= \text{0.012 50 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O } \times \dfrac{\text{296.15 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}{\text{1 mol Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}}\\\\= \text{3.70 g Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}\\\text{You need $\large \boxed{\textbf{3.70 g}}$ of Na$_{2}$CO$_{3}\cdot$10H$_{2}$O}

2. Dilute the solution

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = ?;            c₁ = 0.0500 mol·L⁻¹

V₂ = 100 mL; c₂ = 0.0250 mol·L⁻¹

Calculation:

\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\V_{1}\times \text{0.0500 mol/L} & = & \text{100 mL} \times\text{0.0250 mol/L}\\0.0500V_{1}& = & \text{2.500 mL}\\V_{1}&=& \dfrac{\text{2.500 mL}}{0.0500}\\\\& = &  \text{50.0 mL}\\\end{array}\\\text{You need $\large \boxed{\textbf{50.0 mL}}$ of the concentrated solution.}

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3 years ago
State the law of conservation of mass
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It’s basically that’s any system that’s closed to all transfers of matter and energy the mass of the system has to remain constant over time because they can’t change meaning you can’t add or remove from it

8 0
3 years ago
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