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Natasha_Volkova [10]
3 years ago
12

Los isomeros ópticos

Chemistry
1 answer:
krek1111 [17]3 years ago
7 0

Answer:

Los isómeros ópticos son dos compuestos que contienen el mismo número y tipo de átomos, y enlaces (es decir, la conectividad entre los átomos es la misma), y diferentes disposiciones espaciales de los átomos, pero que tienen imágenes especulares no superponibles. Cada estructura de imagen especular no superponible se denomina enantiómero.

Explanation

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The average rate of disappearance of ozone in the reaction 2o3(g) → 3o2(g) is found to be 7.25×10–3 atm over a certain interval
worty [1.4K]
<h3><u>Answer</u>;</h3>

1.0875 x 10-2 atm

<h3><u>Explanation;</u></h3>

2O3(g) → 3O2(g)

rate = -(1/2)∆[O3]/∆t = +(1/3)∆[O2)/∆t  

The average rate of disappearance of ozone ... is found to  

be 7.25 × 10–3 atm over a certain interval of time.

This means (ignoring time)

∆[O3]/∆t = -7.25 × 10^–3 atm  

(it is disappearing, thus the negative sign)

rate = -(1/2)∆[O3]/∆t  

rate = -(1/2)*(-7.25 × 10^–3 atm)

      = 3.625 × 10^–3 atm  

Now use the other part of the expression:  

rate = +(1/3)∆[O2)∆t  

3.625 × 10–3 atm = +(1/3)∆[O2)/t  

∆[O2)/∆t = (3)*(3.625× 10^–3 atm)

              = 1.0875 x 10-2 atm over the same time interval

4 0
3 years ago
The reaction of pyrrole with bromine forms predominantly __________. View Available Hint(s) The reaction of pyrrole with bromine
xenn [34]

Answer:

a) 2-bromopyrrole

Explanation:

Our options for this questions are:

a) 2-bromopyrrole

b) 2,3-dibromopyrrole

c) N-bromopyrrole

d) 3-bromopyrrole

To understand how the reaction works we have to start with the <u>resonance structures</u>. (Figure 1), on these structures, we will obtain a n<u>egative charge on carbon 2</u> in the pyrrole ring, therefore on this carbon we can generate an attack to an electrophile.

The second step is to check how the mechanism take place. An <u>electrophile is generated</u> by the Br_2 and FeBr_3. This electrophile can be <u>attacked</u> by the negative charge on carbon 2 producing the 2-bromopyrrole. (See figure 2).

I hope it helps!

5 0
3 years ago
What is the density of a 4400. g/cm^3gram brick that is 5.00 inches x 3.00 inches x 2.00 inches?
erica [24]
Density 727838382737737383
7 0
3 years ago
Write the reaction of crystal violet with 1 equivalent of HCl.
tankabanditka [31]

The reaction of crystal violet with 1 equivalent of HCl will be when leuco crystal reacts with HCl to crystal violet it forms hexamethyl pararosaniline chloride.

<h3>What are crystal violet?</h3>

These are the trinary methane compounds mainly used for staining and dying of anything like bacteria or fungi and other name for it is methyl violet 10 B.

In reaction the HCl gets protonated and lone pair of nitrogen atom gives them positive charge.

3C6H6(3NH)3 + HCl will give 3C6H6(3NH)3NH4Cl + 2H

Therefore, reaction of crystal violet with 1 equivalent of HCl will be when leuco crystal reacts with HCl to crystal violet it forms hexamethyl pararosaniline chloride.

learn more about crystal violet, here:

brainly.com/question/12305949

#SPJ1

3 0
1 year ago
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
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