42500 milliliters to kiloliters
2 answers:
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Answer:
(a) g = 8.82158145.
(b) 7699.990192m/s.
(c)5484.3301s = 1.5234 hours.(extremely fast).
Explanation:
(a) Strength of gravitational field 'g' by definition is
, here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.
r = 6721,000 meters, putting this value in above equation gives g = 8.82158145.
(b) We have to essentially calculate centripetal acceleration that equals new 'g'.
here g is known, r is known and v is unknown.
plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.
(c) S = vT, here T is time period or time required to complete one full revolution.
S = earth's circumfrence , V is calculated in (B) T is unknown.
solving for unknown gives T = 5484.3301s = 1.5234hours.
(a) The screen is 3.20m from the split.
(b) The closest minima for green, distance Δy = 0.45 cm.
When a wave hits a barrier or opening, numerous events are referred to as diffraction. It is described as the interference or bending of waves via an aperture or around the corners of an obstruction into the area that forms the geometric shadow of the obstruction or aperture.
(a)Equation of minima = sinθ = mλ/α
Given, m = 3, λ = 6.33X10⁻⁷, α = 0.00015
Putting the values in formula to get θ.
θ = sin⁻¹ ( ) = 0.01266 rad
triangle need to be drawn to find relationship between θ, y$ and L
tan(θ) = y/L where; y = 4.05 cm
L = y/tan(θ) = 3.20
Hence, the screen is 3.20m from the split.
(b) Find the closest minima for green
minima equation is sinθ = mλ/α where, m = 4 (minima with smallest distance)
sinθ = 4λ/α
θ = sin⁻¹ () = 0.01688 rad
Calculate L using
tanθ = y/L
L = 4.5 cm
From equation subtract y₃ from y:
4.50 cm - 4.05 cm = 0.45 cm
Hence, distance Δy = 0.45 cm.
Learn more about the Diffraction with the help of the given link:
#SPJ4
I understand that the question you are looking for is "Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm slit. On the ot
Question
Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm slit. On the other side of the slit is a white screen. When the red laser is turned on, it creates a diffraction pattern on the screen.
a. The distance y3,red from the center of the pattern to the location of the third diffraction minimum of the red laser is 4.05 cm. How far L is the screen from the slit? Express this distance L in meters to three significant figures.
b. With both lasers turned on, the screen shows two overlapping diffraction patterns. The central maxima of the two patterns are at the same position. What is the distance Δy between the third minimum in the diffraction pattern of the red laser (from Part A) and the nearest minimum in the diffraction pattern of the green laser?