The disk's average angular speed during those 5 seconds was
(1/2) (100 + 300) rad/s = 200 rad/sec
Spinning for 5 sec at an average angular speed of 200 rad/s, the disk turned
(200 rad/s) x (5 s) = <em>1,000 radians</em>
(That's 500/pi revolutions = roughly 159.2 revolutions.)
When we look at the moon from the Earth, we always see the same light spots, dark spots, and shapes. It never changes. There could be two possible reasons for this:
-- The moon is a flat disk with some markings on it, and one side of it always faces the Earth.
-- The moon is a round ball with some markings on it, and one side of it always faces the Earth.
Either way, since the same side always faces the Earth, the only way that can happen is if the moon's revolution around the Earth and rotation on its axis both take EXACTLY the same length of time.
Even if they were only one second different, then we would see the moon's whole surface over a long period of time. But we don't. So the moon's rotation and revolution must be EXACTLY locked to the same period of time.
C is correct because they would repel each other A is wrong be they wouldn't repel And B is wrong because they shouldn't be repelling each other
Answer:
a) Resistivity=R.A/L
Here, R=500000ohm, L=1.6m, A=2pi* (0.14/2)*0.002 m2=0.00088.........we have converted quantities into SI units
Resistivity=R.A/L
=500000*0.00088/1.6 = 440/1.6= 275 ohm.meter
b) pskin/pinterior =275/4.8=57.3
For second part, correct option is (A), because cross section area is smaller.
Answer: A combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.
Explanation:
The term standard temperature and pressure is also known as STP and it is most commonly used when we want to calculate the density of a gas.
The term standard temperature means
Fahrenheit or
or 273 Kelvin. On the other hand, term standard pressure means 1 atmosheric pressure of a gas.
Thus, we can conclude that a combination 0 degrees Celsius and 101.3 kPa or 1 atm correctly describes standard temperature and pressure.