Answer:
The magnitude of gravitational force between two masses is
.
Explanation:
Given that,
Mass of first lead ball, 
Mass of the other lead ball, 
The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m
We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

So, the magnitude of gravitational force between two masses is
. Hence, this is the required solution.
5m/s
Explanation:
Given parameters:
Mass of ball = 0.1kg
Force on the ball = 5N
time taken = 0.1s
Unknown:
final speed of the ball = ?
Solution:
According to newton's second law "the net force on a body is the product of its mass and acceleration".
Force = mass x acceleration equation 1
Acceleration =
V is the final velocity
U is the initial velocity
T is the time taken
U = O since it is a stationary body;
a = 
Input "a" into equation 1
F = m x 
5 = 0.1 x 
V = 5m/s
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Answer:
Wash your hand when you are done using the restroom because you could spread germs if not.
Don't come to school if you are sick because then you will get others sick.
Explanation:
Answer:
F = 3600 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of force must be equal to the product of mass by acceleration.
ΣF = m*a
where:
F = force [N]
m = mass = 2000 [kg]
a = acceleration = 1.8 [m/s^2]
Now replacing:
F = 2000*1.8
F = 3600 [N]
Answer:
The burden distance is 7 ft
Solution:
As per the question:
Specific gravity of package emulsion, 
Specific gravity of diabase rock, 
Diameter of the packaged sticks, d = 3 in
Now,
To calculate the first trail shot burden distance, B:
![B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2SG_%7BE%7D%7D%7BSG_%7BR%7D%7D%20%2B%201.5%5D%5Ctimes%20d)
![B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22](https://tex.z-dn.net/?f=B%20%3D%20%5B%5Cfrac%7B2%5Ctimes%201.25%7D%7B2.76%7D%20%2B%201.5%5D%5Ctimes%203%20%3D%207.22)
B = 7 ft