Answer:
1. 
2. 
3. 
Explanation:
Given:
- mass of slinky, 

 
- length of slinky, 

 
- amplitude of wave pulse, 

 
- time taken by the wave pulse to travel down the length, 

 
- frequency of wave pulse, 

 
1.



2.
<em>Now, we find the linear mass density of the slinky.</em>


We have the relation involving the tension force as:




3.
We have the relation for wavelength as:



 
        
             
        
        
        
Answer:
The answers to the questions have been solved in the attachment.
Explanation:
The answers to part a to e are all contained in the attachment. For answer part b, temperature and frequency were assumed to be fixed or constant. V² is directly proportional to T telling us that variation in T gives us a square in the frequency variation. This tells us why it is difficult when both frequencies are on this side of the black body.
 
        
             
        
        
        
Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment. 
<h3>What is Batesian mimicry?</h3>
Batesian mimicry can be defined as a type of adaptive feature associated with the coloration of a particular species and/or population.
On the first island, the color of the population won't change because of the absence of predators. 
On the second island, the color of the population will change because of the presence of predators that can be alerted by the color. 
On the third island, the color of the population won't change because of the presence of a species with a similar color. 
In conclusion, Batesian mimicry is an adaptive feature associated with the coloration of a given species in a given environment. 
Learn more about Batesian mimicry here:
brainly.com/question/14139071
#SPJ1
 
        
             
        
        
        
At its maximum height, the ball will have zero vertical velocity, so the ball's velocity at this point is exactly equal to its horizontal velocity.
At any time <em>t</em>, the horizontal component of its velocity is
<em>v</em> = (15 m/s) cos(40°) ≈ 11.49 m/s
so at the highest point of its trajectory, the ball has a velocity of about 11.49 m/s pointed in the positive horizontal direction.