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Tom [10]
3 years ago
10

A tractor pulls a 978 kg wagon at a velocity of 4.9 m/s. How many watts of power are exerted by the tractor motor is the tractor

pulls the wagon at a 60 degree angle?
Physics
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

23481.78 W

Explanation:

The computation of number of watts of power is shown below:

M = 978 kg

V = 4.9 m/s

Theeta = 60°

As we know that  

 P = Fcos(theeta).V

F = Mg

P = (Mg)cos(theeta).V

P = 978×9.8×cos(60)×4.9

P = 23481.78 W

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A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300
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Answer:

   v = 306.76 Km/h

Explanation:

given,

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speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

          \dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}

where ρ is the density of the air at 3000 m

          v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}

          v= \sqrt{\dfrac{2 \times 3300}{0.909}}

          v = \sqrt{7260.726}

                 v = 85.21 m/s

          v= 85.21 \times \dfrac{3600}{1000}

                 v = 306.76 Km/h

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3 years ago
Sally runs 10,000 meter race at an average speed of 3.5m/s what does average speed mean
aleksandr82 [10.1K]

Answer:

The average speed of 3.5 m/s means that it takes Sally approximately 47.619 minutes to run 10,000 meters

Explanation:

Average speed is a scalar quantity that is given by dividing the total distance moved or traveled by an object by the time that it takes the object during the motion

The average peed indicates the rate at which the object makes a given amount of journey distance given that the journey is completed with varying speeds

With the knowledge of the average speed and the distance covered, the time for completion of the journey can be found as follows;

Average \ speed , \overline v = \dfrac{\Delta x}{\Delta t}

Where

\overline v = Average speed of the object = 3.5 m/s

Δt = The time it takes the Sally to run 10,000 meters

Δx = The total distance Sally runs = 10,000 meters

Therefore;

\Delta t = \dfrac{\Delta x}{ \overline v} = \dfrac{10,000 \ m}{3.5 \ m/s}  = \dfrac{20,000}{7} \ s \approx 2,857.143 \ s

The time it takes the Sally to run 10,000 meters= Δt = 20,000/7 seconds ≈ 2,857.143 seconds

20,000/7 seconds ≈ 47.619 minutes

Therefore, the average speed of 3.5 m/s means that the time it takes the Sally to run 10,000 meters ≈ 47.619 minutes

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3 years ago
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