Question

The equilibrium constant for reaction (1) below is 276. Under the same conditions, what is the equilibrium constant of reaction (2) ? (Think about the basic definition !)
(1) 1/2 X2(g) + 1/2 Y2(g) ↔ XY(g)

(2) 2XY(g) ↔ X2(g) + Y2(g)

Answer 1

The equilibrium constant of the reaction is 76176.

What is the equilibrium constant?

In chemistry, the equilibrium constant is used to show the extent to which we can convert reactants to products in a given chemical process. A large value of the equilibrium constant shows that most of the reactants are converted into products under the given conditions. A small value of the equilibrium constant shows that most of the reactants are not converted into products.

Thus, if we have the reactions;

(1) 1/2 X2(g) + 1/2 Y2(g) ↔ XY(g)

(2) 2XY(g) ↔ X2(g) + Y2(g)

It then follows that;

K1 = [XY]/[X2]^1/2 [Y2]^1/2

K2 =  [XY]^2/[X2] [Y2]

It is clear that;

K2 = (K1)^2

K2 = (276)^2

K2 = 76176

Learn more about equilibrium constant:brainly.com/question/10038290

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