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Zinaida [17]
4 years ago
9

90 grams of glucose, C6H12O6, is dissolved in 2 liters of solution. Determine the molarity (M).

Chemistry
1 answer:
Masja [62]4 years ago
7 0

Answer:

0.25 M

Explanation:

The first step is to determine how many moles of glucose there are, which means first finding out the molar mass of glucose. Carbon has a molar mass of about 12, hydrogen 1, and oxygen 16, so the total molar mass of glucose is about 6(12)+12(1)+6(16)=180 grams. This means that 90 grams is half a mole. Half a mole of substance divided by two liters of solution is (1/2)/2=1/4, or a molarity of 0.25. Hope this helps!

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3 years ago
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Citric acid is one component of some soft drinks. Suppose that 8 L of solution are made from 0.24 g of citric acid, C6H8O7. What
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Answer:

The correct answer is 0.15 × 10⁻³ M.

Explanation:

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The value of the solution given in the question is 8 L.  

The mass of citric acid given is 0.24 g or 240 mg, which can also be written as 240/1000 g or 240 × 10⁻³ g.  

The number of moles can be calculated by using the formula = mass / molar mass. Thus, by putting the values we get,  

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The number of moles of the solute present in the 1 liter of the solution is termed as the molarity of the solution. The formula of molarity or M is,  

= no of moles of solute / volume of solution in L

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4 years ago
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Answer:

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