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2 years ago

(d) If you have 9.44 g of NazPO4, how many grams of AgNO, will be needed for complete

Chemistry

1 answer:

AlladinOne [14]2 years ago

3 0

30.6 g of AgNO₃

Explanation:

We have the following chemical reaction:

Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃

Now we calculate the number of moles of Na₃PO₄:

number of moles = mass / molecular weight

number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles

Now we formulate the following reasoning:

if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃

then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃

X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃

mass = number of moles × molecular weight

mass of AgNO₃ = 0.18 × 170 = 30.6 g

Learn more about:

mole concept

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Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

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