The maximum wavelength, in nm, of light that can eject an electron from the metal, given the data is 467.72 nm
<h3>Data obtained from the question</h3>
From the question given abover, the following data were obtained:
- Energy (E) = 4.25×10¯¹⁹ J
- Wavelength (λ) =?
<h3>How to determine the wavelength of the light </h3>
- Energy (E) = 4.25×10¯¹⁹ J
- Planck's constant (h) = 6.626×10¯³⁴ Js
- Speed of light (v) = 3×10⁸ m/s
- Wavelength (λ) =?
The wavelength of the light can be obtained as illustrated below:
E = hv / λ
Cross multiply
E × λ = hv
Divide both sides by E
λ = hv / E
λ = (6.626×10¯³⁴ × 3×10⁸) / 4.25×10¯¹⁹
λ = 0.00000046772 m
λ = 467.72 nm
Thus, the wavelength of the light that can eject an electron from the metal is 467.72 nm
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