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Tom [10]
2 years ago
5

What is the maximum wavelength, in nm, of light that can eject an electron from a metal with Φ =4.25 x 10–19 J?

Chemistry
1 answer:
Marysya12 [62]2 years ago
8 0

The maximum wavelength, in nm, of light that can eject an electron from the metal, given the data is 467.72 nm

<h3>Data obtained from the question</h3>

From the question given abover, the following data were obtained:

  • Energy (E) = 4.25×10¯¹⁹ J
  • Wavelength (λ) =?

<h3>How to determine the wavelength of the light </h3>
  • Energy (E) = 4.25×10¯¹⁹ J
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Speed of light (v) = 3×10⁸ m/s
  • Wavelength (λ) =?

The wavelength of the light can be obtained as illustrated below:

E = hv / λ

Cross multiply

E × λ = hv

Divide both sides by E

λ = hv / E

λ = (6.626×10¯³⁴ × 3×10⁸) / 4.25×10¯¹⁹

λ = 0.00000046772 m

λ = 467.72 nm

Thus, the wavelength of the light that can eject an electron from the metal is 467.72 nm

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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∴ pOH = - Log [OH-]

⇒ pOH = 3.62

⇒ pH = 14 - pOH = 14 - 3.62 = 10.38

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