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Tom [10]
1 year ago
5

What is the maximum wavelength, in nm, of light that can eject an electron from a metal with Φ =4.25 x 10–19 J?

Chemistry
1 answer:
Marysya12 [62]1 year ago
8 0

The maximum wavelength, in nm, of light that can eject an electron from the metal, given the data is 467.72 nm

<h3>Data obtained from the question</h3>

From the question given abover, the following data were obtained:

  • Energy (E) = 4.25×10¯¹⁹ J
  • Wavelength (λ) =?

<h3>How to determine the wavelength of the light </h3>
  • Energy (E) = 4.25×10¯¹⁹ J
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Speed of light (v) = 3×10⁸ m/s
  • Wavelength (λ) =?

The wavelength of the light can be obtained as illustrated below:

E = hv / λ

Cross multiply

E × λ = hv

Divide both sides by E

λ = hv / E

λ = (6.626×10¯³⁴ × 3×10⁸) / 4.25×10¯¹⁹

λ = 0.00000046772 m

λ = 467.72 nm

Thus, the wavelength of the light that can eject an electron from the metal is 467.72 nm

Learn more about energy:

brainly.com/question/10703928

#SPJ1

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The masses of carbon and hydrogen in samples of four pure hydrocarbons are given above. The hydrocarbon in which sample has the
enot [183]

Answer:

Sample B

Explanation:

In this case, we need to determine the empirical formula for each sample. The one that match the formula of the propene would be the sample.

Let's do Sample A:

C: 60 g;       H: 12 g

1. Calculate moles:

We need the atomic weights of carbon (12 g/mol) and hydrogen (1 g/mol):

C: 60 / 12 = 5

H: 12 / 1 = 12

2. Determine number of atoms in the formula

In this case, we just divide the lowest moles obtained in the previous part, by all the moles:

C: 5 / 5 = 1

H: 12 / 5 = 2.4    or rounded to two

3. Write the empirical formula:

Now, the prior results, represent the number of atoms in the empirical formula for each element, so, we put them with the symbol and the atoms as subscripted:

C₁H₂ = CH₂

Therefore, sample A is not the same as propene.

Sample B:

C: 72 g    H: 12 g

Following the same steps, let's determine the empirical formula for this sample

C: 72 / 12 = 6 ---> 6 / 6 = 1

H: 12 / 1 = 12 ----> 12 / 6 = 2

EF: CH₂

Sample C:

C: 84 g    H: 10 g

C: 84 / 12 = 7 ----> 7 / 7 = 1

H: 10 / 1 = 10    ----> 10 / 7 = 1.4 or just 1

EF: CH

Sample D

C: 90 g      H: 10 g

C: 90 / 12 = 7.5     -----> 7.5 / 7.5 = 1

H: 10 / 1 = 10  -------> 10 / 7.5 = 1.33 or just 1

EF: CH

Neither compound has the same empirical formula as C3H6, but C3H6 is a molecular formula, so, if we just simplify the formula we have:

C3H6  -----> CH₂

Therefore, sample B is the one that match completely. Sample B would be the one.

Hope this helps

8 0
3 years ago
ESKER <br><br> what is an esker, no copy and paste, in ur own words
ahrayia [7]
An esker is a winding ridge that is typically composed of gravel/assorted sediment that has been created from the melting/departure of a glacier. They usually span a long distance.
4 0
2 years ago
Part A Transmutation is the process of transforming one element into another through nuclear reactions. What will be the nuclide
S_A_V [24]

<u>Answer:</u> The isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

<u>Explanation:</u>

Transmutation is defined as the process where one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of Californium-249 nucleus with Carbon-12 nucleus follows:

_{98}^{249}\textrm{Cf}+_6^{12}\textrm{C}\rightarrow _{Z}^{A}\textrm{X}+4_0^1\textrm{n}

In a nuclear reaction, the total mass and total atomic number remains the same.

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

249 + 12 = A + 4

A = 257

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

98 + 6 = Z + 0

Z = 104

Hence, the isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

5 0
3 years ago
What are the three particles of an atom
g100num [7]
The three particles of any atom are
<u>electron</u>) the smallest particle and is held in shells around the nucleus of the atom
<u>proton</u>) is found in the nucleus and is much larger than an electron
<u>neutron</u>) the same mass as a proton and also found in the nucleus of the atom
5 0
3 years ago
Read 2 more answers
The empirical formula for a compound is ch2o and the molar mass is 180.2g mol which is molecular formula for this compound
elena-14-01-66 [18.8K]
Answer:
                Molecular Formula  =  C₆H₁₂O₆

Solution:

Molecular formula is calculated by using following formula,

                     Molecular Formula  =  n × Empirical Formula  ---- (1)

Also, n is given as,

                      n  =  Molecular Weight / Empirical Formula Weight

Molecular Weight  =  180.2 g.mol⁻¹

Empirical Formula Weight  =  12 (C) + 2 (H₂) + 16 (O)  =  30 g.mol⁻¹
Son
                      n  =  180.2 g.mol⁻¹ ÷ 30 g.mol⁻¹

                      n  =  6

Putting Empirical Formula and value of "n" in equation 1,

                     Molecular Formula  = 6 × CH₂O

                     Molecular Formula  =  C₆H₁₂O₆
7 0
3 years ago
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