(C) 0.1 mole of NaCl dissolved in 1,000. mL of water
<u>Explanation:</u>
The conductivity of 0.1 mole of NaCl dissolved in 1000 mL of water will be greatest as the number of ions in 0.1 mole of NaCl will be more than 0.001, 0.05 and 0.005 moles of NaCl. Greater the number of ions in the solution, greater will be the conductivity. Specific Conductivity decreases with a decrease in concentration. Since the number of ions per unit volume that carry current in a solution decrease on dilution. Hence, concentration and conductivity are directly proportional to each other.
The partial pressure of oxygen given the total barometric pressure is : 108.15 mmHg
<u>Given data : </u>
Total barometric pressure = 515 mmHg
Assuming oxygen percentage = 21%
Barometric pressure dry at 37°C
<h3 /><h3>Determine the partial pressure of oxygen </h3>
Applying the relation below
Partial pressure = oxygen percentage * Barometric pressure
= 21% * 515 mmHg
= 108.15 mmHg
Hence we can conclude that the partial pressure of oxygen is 108.15 mmHg.
Learn more about Partial pressure : brainly.com/question/1835226
The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m
<h3>What is Stack Height ?</h3>
Stack height means the distance from the ground-level elevation at the base of the stack to the crown of the stack.
If a stack arises from a building or other structure, the ground-level elevation of that building or structure will be used as the base elevation of the stack.
Given is a steel stack that exhausts 1,200 cu.m/min of gases
P= 1 atm and
T= 400 K
maximum expected wind speed at stack height of 12 m/s
The formula for the diameter of chimney

Q =1200 cu.m/min
= 1200 * 0.0166 = 19.92 cu.m/sec
Velocity = 12m/s

d= 1.45 m
Therefore The inner diameter for a steel stack that exhausts 1,200 m3/min of gases at 1 atm and 400 k is 1.45 m.
To know more about Stack Height
brainly.com/question/24625453
#SPJ4
Answer:
42.38875878%
Explanation:
i divided 4.27 g from 1.81g using a percentage calculator but im not sure if its correct