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Alika [10]
1 year ago
10

What is the rate of change of the function represented by the table?

Mathematics
2 answers:
oee [108]1 year ago
5 0

The rate of change of the function represented by the table is -2.5

<h3>Rate of change</h3>

The rate of change of a function is also known as its slope. The formula for calculating the slope is expressed as;

Slope = y2-y1/x2-x1

Using the coordinate point (1, -8.5) and (2, -6) as given in the table, the rate of change is expressed as:

Rate of change =-6-(-8.5)/2-1
Rate of change = -6+8.5/1
Rate of change = 2.5

Hence the rate of change of the function represented by the table is -2.5

Learn more on rate of change here: brainly.com/question/8728504

#SPJ1

True [87]1 year ago
5 0

Answer:

To keep it short it’s A lol:)

Step-by-step explanation:

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which equation is the quadratic variation equation for the relatonship? the variable y varies directly with x^2 and y=36 when x=
svetoff [14.1K]

For this case we have a direct variation of the form:

y = kx ^ 2

Where,

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We must find the value of k.

For this, we use the following data:

y = 36\\x = 3

Therefore, replacing values we have:

36 = k (3) ^ 2

Rewriting:

36 = 9k

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Answer:

The quadratic variation equation for the relatonship is:

y = 4x ^ 2

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3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 108.7-cm and a standard dev
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Let x be the lengths of the steel rods and X ~ N (108.7, 0.6)

To get the probability of less than 109.1 cm, the solution is computed by:


z (109.1) = (X-mean)/standard dev

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= 1.1/0.6

=1.83333, look this up in the z table.


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Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

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5 0
3 years ago
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