The sum of 2 numbers is 45. The larger number y is 6 less than twice the smaller number X. What is the smaller number?
2 answers:
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Answer:
5040,56
Step-by-step explanation:
We have to construct pass words of 4 digits
a) None of the digits can be repeated
We have total digits as 0 to 9.
4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)
No of passwords = 10P4
=
b) start with 5 and end in even digit
Here we restrain the choices by putting conditions
I digit is compulsorily 5 and hence only one way
Last digit can be any one of 0,2,4,6,8 hence 5 ways
Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)
=56
The answer is a =
Step-by-step explanation:
<em>1. Convert the mixed fraction to an improper fraction</em>
To find the numerator, multiply the denominator by the whole number and add the numerator to it.
The denominator remains the same.
So, 2 will be
<em>2. Now the equation is,</em>
a -
a =
+
a
<em>3. Take LCM on both sides. </em>
For the left side, multiply the first fraction by and multiply the second fraction by
a -
a =
<em>4. Solve by making a the subject</em>
=
=
=10+8a
= 10 + 8a
a = 2(10 + 8a)
a = 20 + 16a
a-16a = 20
-15a = 20
a =
a =
Therefore, the answer is a =
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