Check the picture below.
so the lateral area will be just the area of the sides, namely excluding the bases at top and bottom, thus
![\stackrel{\textit{\LARGE Lateral Area}}{\stackrel{\textit{front and back}}{2(4)(5)}~~ + ~~\stackrel{\textit{left and right}}{2(4)(7)}}\implies 40~~ + ~~56\implies 96~cm^2](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7B%5CLARGE%20Lateral%20Area%7D%7D%7B%5Cstackrel%7B%5Ctextit%7Bfront%20and%20back%7D%7D%7B2%284%29%285%29%7D~~%20%2B%20~~%5Cstackrel%7B%5Ctextit%7Bleft%20and%20right%7D%7D%7B2%284%29%287%29%7D%7D%5Cimplies%2040~~%20%2B%20~~56%5Cimplies%2096~cm%5E2)
3 x
---------= --------- ---------
15 180
15x=540
----- ------= 36 students.
15 15
Steps: Cross multiply to get 15x and 540. Divide both numbers by 15, then you found what x equals, which is the answer.
Answer:
$54
Step-by-step explanation:
Since its $0.24 per 1 square inch, you would multiply 0.24 by the total amount of square inches. When we do this, we get 54 as our answer.\
Hope this helps!
Answer:
129 = QRX
Step-by-step explanation:
The exterior angle is equal to the sum of the opposite interior angles
49+80 = QRX
129 = QRX
Your trying to move -8p to the right side , so first add 12 to 14 the -12 + 12 is zero and add 12 to plus then it would end up to -8p=5p+ whatever your number is the you look for p