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OverLord2011 [107]

3 years ago

6

What do high pressure systems usually cause A: CLEAR, DRY WEATHER B: CLOUDY, WET WEATHER C: COLD, WET WEATHER D: HOT AND HUMID W

EATHER

1 answer:

Triss [41]3 years ago

5 0

C. Clear, dry weather. A good way to remember is H for high pressure = H for happy weather; L for low pressure = L for lousy weather (Glad I had someone to tell me this)

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9.58 A spring of equilibrium length L1 and spring constant k1 hangs from the ceiling. Mass m1 is suspended from its lower end. T

andrey2020 [161]

Answer:

The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.

See attachment below for full solution

Explanation:

This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.

4 0

4 years ago

In which scenario does radiation occur?

kaheart [24]

Pretty sure a, because it’s a stove and it uses electricity like almost a normal appliance for the kitchen would, the rest are just a natural force without any radiation to occur in them, electricity is the same as technology and believe it or not technology like phones give off radiation, so yeah. hope this was helpful!

7 0

3 years ago

Read 2 more answers

Wet sugar that contains one-fifth water by mass is conveyed through an evaporator in which 85% of the of the entering water is e

Natalka [10]

Answer:

a)

i) $v'=\frac{17}{20}$ ii) $\frac{m_v}{m_f-m_v} =\frac{17}{83}$

b) $m_r=752963.55\ kg$

Explanation:

Given:

fraction of water in wet sugar of m kg by mass, $m'_w=\frac{1}{5} \times m$

% of water evapourated from the total water after passing through the evapourator, $m'_v=85\%$

a)

amount of wet sugar fed to the evapourator, $m_f=100\ kg$

Now the mass of water present in the fed amount of sugar:

$m_w=\frac{1}{5} \times m_f$

$m_w=\frac{100}{5}$

$m_w=20\ kg$

Now the amount of water leaving from this total amount of water after passing through the evapourator:

$m_v=m_v' \times m_w$

$m_v=\frac{85}{100} \times 20$

$m_v=17\ kg$

i)

So, the fraction of of water leaving the evapourator:

$v'=\frac{m_v}{m_w}$

$v'=\frac{17}{20}$

ii)

Now the ratio of kg water vaporized/kg wet sugar leaving the evaporator.:

$\frac{m_v}{m_f-m_v} =\frac{17}{100-17}$

$\frac{m_v}{m_f-m_v} =\frac{17}{83}$

b)

amount of sugar fed per day, $m_f=907185\ kg$

<u>Now the mass of water in the given amount of sugar per day:</u>

$m_w=\frac{m_f}{5}$

$m_w=\frac{907185}{5}$

$m_w=181437\ kg$

Mass of water vapourized after passing through the evaporator:

$m_v=\frac{85}{100}\times m_w$

$m_v=\frac{85}{100}\times 181437$

$m_v=154221.45\ kg$

Now the mass of water still remaining in the sugar:

$m_r=m_w-m_v$

$m_r=907185-154221.45$

$m_r=752963.55\ kg$

is the mass of extra water to be evapourated.

8 0

3 years ago

The core muscles stabilize and protect the spine.

Aleksandr [31]

True. yes the core muscles stabilize and protect the spine.

4 0

3 years ago

Read 2 more answers

Calculate the heat energy required to convert 4kg of ice at -25℃, to stem, at 100℃, given the specific heat capacity of water is

ira [324]

Answer:

1,840,000 J

Explanation:

The energy required for a particular change in state is given by the specific latent heat. Specific latent heat is the amount of energy required to change the state of 1 ... of ice into 1 kg of water at its melting point of 0°C. The same amount of energy ... stored or released as the temperature of a system changes can be calculated.

5 0

3 years ago