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soldier1979 [14.2K]
2 years ago
10

Identify the products of the reaction between mercury(ii) sulfate and titanium(ii) nitrate.

Chemistry
1 answer:
Lisa [10]2 years ago
4 0

The product of the reaction between mercury (ii) sulfate and titanium (ii) nitrate is Mercury(I) nitrate and titanium sulfate.

<h3>What is a chemical reaction?</h3>

A chemical reaction is one in which two or more substances react to form a totally different product. The reactants are called reactants and the formed suitcase is called the product.

The reaction between mercury (ii) sulfate and titanium (ii) nitrate is given below: when mercury sulfate reacts with titanium nitrate, Mercury(I) nitrate and titanium sulfate.

HgSo₄ + Ti(NO₃) = HgNO₃ + TiSO₄

Thus, the product is Mercury(I) nitrate and titanium sulfate.

To learn more about chemical reaction, refer to the link:

brainly.com/question/13483423

#SPJ1

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vekshin1
Phenolphthalein is not a good indicator to use for a titration for a solution that has a ph of 6.0 at the equivalence point because the color change of the solution at this pH level is not sharp. It changes the color of the solution to pink starting from pH 8.3 to 10. A pH level lower than 8.3  would only show a colorless solution. Thus, you would not be able to distinguish whether the solution has reached its equivalence point at pH 6.0. It is best to use this indicator for a system that is using a strong base titrated with a weak acid.
5 0
3 years ago
Look at the potential energy diagram for a chemical reaction.
vladimir1956 [14]

Answer: The activation energy is 10 kJ and the reaction is exothermic.

Explanation: Exothermic reactions are those in which heat is released and thus the energy of products is less than the energy of reactants.

Endothermic reactions are those in which heat is absorbed and thus the energy of products is more than the energy of reactants.

Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to convert to products.

Given : Energy of reactants = 40kJ

Energy of activation: (50-40)=10 kJ

Energy of products = 50 kJ

Energy of products = 15 kJ

Thus Energy of products (15kJ) < Energy of reactants(40kJ), the reaction is exothermic as energy has been lost to surroundings in the form of heat.

8 0
4 years ago
Problem page gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o
iVinArrow [24]

m(\text{CO}_2) = 2.24 \; \text{g}

Ethene react with oxygen at a 2 : 7 molar ratio:

2\; \text{C}_2 \text{H}_6 (g) + 7\; \text{O}_2 (g) \to 6\; \text{H}_2{O} (g) + 4\; \text{CO}_2 (g)

Convert the quantity of each reactant supplied to number of moles of particles:

  • n(\text{C}_2\text{H}_6) = 0.60 \; \text{g} / 28.05 \; \text{g} \cdot \text{mol}^{-1} =  0.0214 \; \text{mol}
  • n(\text{O}_2) = 3.27 \; \text{g} / 32.00 \; \text{g} \cdot \text{mol}^{-1} =  0.102 \; \text{mol}

The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species, n(\text{C}_2 \text{H}_6) /2 and n(\text{O}_2) /7 (as seen in the balanced chemical equation) shall satisfy the relationship

n(\text{O}_2) / 7 - n(\text{C}_2 \text{H}_6) / 2 > 0

In other words,

n(\text{O}_2)/7 > n(\text{C}_2 \text{H}_6)/2

n(\text{C}_2 \text{H}_6) / n(\text{O}_2) < 2/7 \approx 0.286

Evaluating the expression n(\text{C}_2 \text{H}_6) / n(\text{O}_2) with data given in the question yields approximately 0.210 < 0.286, which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.

The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio n(\text{C}_2\text{H}_6) : n( \text{CO}_2) = 2:4,

n(\text{CO}_2) = n(\text{C}_2\text{H}_6) \cdot (2 / 4) = 0.0510 \; \text{mol}

m(\text{CO}_2) = 0.0510 \; \text{mol} \times 44.01 \; \text{g} \cdot  \text{mol}^{-1} = 2.24 \; \text{g}

4 0
3 years ago
Estimate the percent ionic character of the co bond. (note that the electronegativity of c is 2.5 and that of o is 3.5.)
deff fn [24]

From the calcuation, the percent ionic character of the bond is  70%

<h3>What is percent ionic character?</h3>

The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.

We can use the formula; 100(1 - e^(-ΔEN² / 4))

EN = χB − χA * 100/1

EN = 3.5 - 1.5 = 1

100(1 - e^(-1)^2/4)

= 70%

Learn more about percent ionic character:brainly.com/question/7034446

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5 0
2 years ago
What are the three elements found in a molecule of calcium carbonate? Give their atomic numbers and chemical symbols. How many a
Thepotemich [5.8K]
Calcium carbonate is CaCO3.
So there is calcium, symbol is Ca and an atomic number of 20.
Carbon: symbol is C and an atomic number of 6.
Oxygen: symbol is O and an atomic number of 8.
In one molecule of CaCO3, there is one atom of Ca, one atom of C, and three atoms of O as shown by the subscript next to O in the formula. There are no other subscripts to indicate more than one atom of the other elements, so there is only one atom of the other two elements
7 0
3 years ago
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