The Urease test recognizes living beings that are equipped for hydrolyzing urea to deliver smelling salts and carbon dioxide. It is utilized to recognize urease positive Proteeas from other Enterobacteriaceae.
It is a huge group of microscopic organisms, which are Gram-negative and bar mold. They are chemo-organotrophic and can develop in the nearness or nonappearance of air. There are numerous genera, found as parasites and pathogens in an extensive variety of life forms from plants to people.
Answer: The products are sodium acetate 
and solid silver chloride 
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The reaction of aqueous solutions of sodium chloride and silver (I) acetate is :
Thus the products are aqueous sodium acetate and solid silver chloride
Explanation:
This process ensures that the pressure inside of the graduated cylinder is the same as the atmospheric pressure in the room.
Suppose the level of water inside and outside the cylinder is same, pressure stays the same. Therefore, total pressure of the is made equal to atmospheric pressure by adjusting the height of cylinder. it is done till the water level is equal.
Answer:
The products will be;
CO₂ + H₂O + NaC₂H₃O₂
Explanation:
We are given;
Two reactants NaHCO₃ and HC₂H₃O₂
We are supposed to determine the products;
- We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.
Therefore;
- In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
- The equation for the reaction is;
NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂
- Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂
