The answer is 98ppm.
The ppm (Parts per million) is also a concentration unit. 1 ppm is equivalent to 1mg/L
Now, concentration of the solution of sulfuric acid is 0.0980 g/L.
We rewrite, 0.0980 g = 0.0980*1000 mg = 98mg
Therefore, the concentration of the sulfuric acid solution is 98 mg/L = 98 ppm.
Answer:
112.2L
Explanation:
Volume (V) = 300g
Temperature (T) = 822K
Pressure (P) = 0.9atm
using the ideal gas equation;

Molar gas constant (R) = 
Mole (n) =
Molar mass of Mercury = 200.59g/mol

= 1.496mol
Now, the volume can be calculated;
V = 
∴Volume of mercury = 
Balanced Half reactions are:
At anode 2
==> Cl₂+
+ H₂O ==>
+ 2
+
At Cathode: 2
+
==> H₂
Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O,
,
and 
Now at Anode reaction will occur as given:
2
==> Cl₂+
+ H₂O ==>
+ 2
+
(will occur)
At Cathode:
2
+
==> H₂ (will occur)
At Cathode:
+
==> Mn (This reaction will not occur)
The deposition of solid Mn will not occur because in aqueous solution,
will be reduced before
.
The reduction potentials for
is zero whereas reduction potential for
is - 1.18V.
The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.
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Answer:
See explanation
Explanation:
Now , we have the equation of the reaction as;
2H2S(g) + 302(g)------->2SO2(g) + 2H2O(g)
This equation shows that SO2 gas is produced in the process. Let us recall that this same SO2 gas is the anhydride of H2SO4. This means that it can dissolve in water to form H2SO4
So, when SO2 dissolve in rain droplets, then H2SO4 is formed thereby lowering the pH of rain water. This is acid rain.
calculate the molar mass of Fe + 3(Cl)
that is your total mass
percent composition of FeCl3
mass % Fe = molar mass FE / total mass X 100 = %
mass % 3Cl = molar mass 3Cl / total mass X 100 = %
that is percent composition
Hope it’s help !!!!