All categories

2 years ago

How did harlow shapley conclude that the sun was not in the center of the milky way galaxy?

Physics

1 answer:

timurjin [86]2 years ago

3 0

We learned that We are in the disk of the Galaxy, about 5/8 of the way from the center.

<h3>What is the work of Harlow Shapley?</h3>

Shapley, who was headquartered in Boulder, Colorado, used Cepheid variable stars to estimate the size of the Milky Way Galaxy and its position relative to the Sun. In 1953, he published his "liquid water belt" theory, today known as the concept of a livable zone.

There are many stars, grains of dust, and gas in the Milky Way. It is known as a spiral galaxy because, from the top or bottom, it would appear to be whirling like a pinwheel. About 25,000 light-years from the galaxy's nucleus, the Sun is situated on one of the spiral arms.

Approximately 5/8 of the way from the galaxy's nucleus, we are in the disc. William Herschel believed that the Sun and Earth were about in the middle of the vast cluster of stars known as the Milky Way.

To learn more about Harlow Shapley's original estimate go to - brainly.com/question/28145909

#SPJ4

You might be interested in

Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:

Deffense [45]

Answer:

a) $T=0.01s$

b) $T=0.001s$

c) $T=0.00001s$

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

$T=\frac{1}{f}$

Therefore

For

$T=100 Hz$

$T=\frac{1}{100}$

$T=0.01s$

For

$F=1kHz$

$T=\frac{1}{1000}$

$T=0.001s$

For

$F=100kHz$

$T=\frac{1}{100*100}$

$T=0.00001s$

6 0

3 years ago

A ball is kicked at a speed of 16m/s at 33° and it eventually returns to ground level further down field.

saw5 [17]

Hi there!

We can begin by calculating the time taken to reach its highest point (when the vertical velocity = 0).

Remember to break the velocity into its vertical and horizontal components.

Thus:

0 = vi - at

0 = 16sin(33°) - 9.8(t)

9.8t = 16sin(33°)

t = .889 sec

Find the max height by plugging this time into the equation:

Δd = vit + 1/2at²

Δd = (16sin(33°))(.889) + 1/2(-9.8)(.889)²

Solve:

Δd = 7.747 - 3.873 = 3.8744 m

4 0

3 years ago

Read 2 more answers

4 (JAMB) The diagram below shows a light see-saw, which is balanced horizontally by the weights W₁, W2, W3, W4 in the positions

damaskus [11]

The equation that represents the principle of the lever balance is:

W₁ + W₂ = W3 + W4; option A.

<h3>What is the principle of moments?</h3>

The principle of moments states when a body is in equilibrium, the sum of the clockwise moment about a point equals the sum of anticlockwise moment about that point.

A see-saw represents a balanced system of moments.

The sum of clockwise moment = The sum of anticlockwise moments.

Assuming W1 and W2 are clockwise moments and W3 and W4 are anticlockwise moments.

The equation will b: W₁ + W₂ = W3 + W4

In conclusion, a balanced see-saw illustrates the principle of the lever balance.

Learn more about principle of moments at: brainly.com/question/20519177

#SPJ1

6 0

2 years ago

Introduced species often thrive and multiply in an environment very different from their original one. Why are they often able t

Anestetic [448]

They begin to adapt into their new location. They then end up having adaptations to help them survive.

8 0

3 years ago

Based on the free-body diagram, the net force acting<br> on this firework is

Strike441 [17]

0N. The net force acting on this firework is 0.

The key to solve this problem is using the net force formula based on the diagram shown in the image. Fnet = F1 + F2.....Fn.

Based on the free-body diagram, we have:

The force of gases is Fgases = 9,452N

The force of the rocket Frocket = -9452

Then, the net force acting is:

Fnet = Fgases + Frocket

Fnet = 9,452N - 9,452N = 0N

4 0

3 years ago

Read 2 more answers