How to find work without force

2 answers:

6 0

I’m not sure what variables you are given, but since work = force x distance, and force = mass x acceleration, you could use work = mass x acceleration x distance

True [87]3 years ago

3 0

You can use Power = Energy/time for problems if that is what you asking for.

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A uniform metal rod of length 80cm and mass 3.2kg is supported horizontally by two vertical spring balance C and D. Balance C is

vagabundo [1.1K]

A uniform metal rod with of length 80cm and a mass of 3.2kg is supported horizontally by two vertical spring balances C and D. Balance C is 20cm from one end while D is 30cm from the other end would show the reading of 1.06 Kg and 2.13 kg respectively

<h3>What is gravity?</h3>

It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another, The gravity varies according to the mass and size of the body for example the force of gravity on the moon is the 1/6th times of the force of gravity on the earth.

As given in the problem, A uniform metal rod of the length of 80cm and mass of 3.2kg is supported horizontally by two vertical springs balance C and D. Balance C is 20cm from one end while D is 30cm from the other end

The weight of the rod acting downward is from the center of the rod at 40 cm

Let us suppose the reading on the spring balance C and D are P and Q respectively

By using the equilibrium for the vertical force

Fv=0

P + C = 3.2

By using the equilibrium for the moment around the left corner

20×P+ 50×Q= 40 ×3.2

By solving for both P and Q from the above two equations we would get

P =1.06 and Q = 2.13

Thus, the reading on the spring balance C and D would be 1.06 Kg and 2.13 kg respectively

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1 year ago

State the principle of floatation

WARRIOR [948]

Explanation:

<em><u>Principle of Floatation</u></em>

Principle of Floatation states that weight of floating body is equal to weight of water displaced by it

7 0

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Lora (of mass 43.6 kg) is an expert skier. She starts at 3.6 m/s at the top of the lynx run, which is 67 m above the bottom. Wha

Likurg_2 [28]

Explanation:

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