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Karolina [17]
3 years ago
13

How to find work without force

Physics
2 answers:
nikklg [1K]3 years ago
6 0
I’m not sure what variables you are given, but since work = force x distance, and force = mass x acceleration, you could use work = mass x acceleration x distance
True [87]3 years ago
3 0
You can use Power = Energy/time for problems if that is what you asking for.
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Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point to
Brut [27]

Answer:

It would point up.

Explanation:

Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.

Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.

So, the compass would point up.

7 0
3 years ago
which changes of state should she place in the column titled "lose energy"?freezing, boiling, and meltingmelting, vaporization,
Blababa [14]
Freezing (liquid to solid)
Deposition (gas to solid)
Condensation (gas to liquid)

All three of these state changes are a result of a energy loss. When considering energy loss it is best to think of situations where temperature has dropped. Less energy in the system results in less energy the substance is exposed to or has available. 
7 0
3 years ago
Read 2 more answers
A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 meter distance by applying a brake. No
kozerog [31]

Answer: -2502N

Explanation:

(V_2)^2=(V_1)^2+2ad

where;

V_2 = final velocity = 0

V_1 = initial velocity = 60 km/h = 16.67 m/s

a = acceleration

d = distance

First all of, because acceleration is given in m/s and not km/h, you need to convert 60km/h to m/s. Our conversion factors here are 1km = 1000m and 1h = 3600s

60km/h(\frac{1000m}{1km} )(\frac{1h}{3600s} )=16.67m/s

Solve for a;

(V_2)^2=(V_1)^2+2ad

Begin by subtracting (V_1)^2

(V_2)^2-(V_1)^2=2ad

Divide by 2d

\frac{(V_2)^2-(V_1)^2}{2d} =a

Now plug in your values:

a=\frac{(0)^2-(16.67 m/s)^2}{2(50m)}

a=\frac{0-277.89m^2/s^2}{100m}

a=-2.78m/s

If you're wondering why I calculated acceleration first is because in order to find force, we need 2 things: mass and acceleration.

F=ma

m = mass = 900kg

a = acceleration = -2.78m/s

F=(900kg)(-2.78m/s)\\F=-2502N

It's negative because the force has to be applied in the opposite direction that the car is moving.

8 0
3 years ago
Мета: :
Ierofanga [76]
I can’t answer this
3 0
3 years ago
NI3 is an extremely sensitive contact explosive Use IUPAC rules to name this compound.
Vinvika [58]
The answer is <span>nitrogen triodide

Did I help?
please mark me brainliest answer.</span>
3 0
3 years ago
Read 2 more answers
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