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BigorU [14]
3 years ago
5

(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500-μC charge and flies due west at a spee

d of 660 m/s over the Earth’s magnetic south pole (near Earth's geographic north pole), where the 8.00×10−5 -T magnetic field points straight down. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect
Physics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

(a) Magnitude of Magnetic force on jet will be 2.64 ×10^{-8} N and direction will be towards South.

(b) The value obtained in part (a) will have negligible effect.

Explanation:

(a) The magnetic force acting on a moving charge is given by :-

<em />\vec{F}<em> = q ( </em>\vec{v} \times \vec{B}<em>)</em>

So, magnitude of Force will be:-

F = 0.5 × 10^{-6} × ( 660 × 8 × 10^{-5} ) × sin (90⁰)

  = 2.64 ×10^{-8} N.

And direction can be found out using Right Hand Thumb Rule.

It comes out to be towards South.

(b)  The gravitational force acting on the jet is massive as the mass of jet is very large. Compared to that, the value obtained above is negligible.

If the jet can overcome gravitational force and fly, the magnetic force will have negligible effect.        

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Answer:

1500 per second.

Explanation:

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Scorpion4ik [409]

Part a:

Q_{1} = 56

Q_{2} = 60

Q_{3} = 63

     The quartiles are found by finding the medium of the data, and then the mediums of the two different data sets on either side of the medium. The Q_{2} is the overall medium, Q_{1} is the medium of the first half, and Q_{3} is the medium of the second half.

-> How is the medium found? When finding the medium we put the values in order least to greatest and pick the middle value.

[] See attached

Part b:

The range is 7.

The interquartile range is the range of numbers between Q_{1} and Q_{3}. In other words, it is 50% of the data, directly in the middle.

This becomes 63 - 56 = 7

Part c:

79 is an outlier.

It is an outlier because it is 1.5 above or below (in this case, above) the interquartile range.

-> 63 + (7 + \frac{7}{2}) ≤ 79

-> 63 + 10.5 ≤ 79

-> 73.5 ≤ 79

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

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2 years ago
Which events took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sol
balu736 [363]
<h2>2) Copernicus rediscovered Aristarchus’s heliocentric model.</h2>

Before Copernican Revolution, people did believe in the ptolemain model that establishes the description of the Universe with the earth at the center having sun, moon, starts and planets all orbited earth. On the other hand, the heliocentric model establishes the sun at the center of the solar system and this starts with the publication of Nicolas Copernicus named <em>De revolutionibus orbium coelestium.</em>

<h2>5) Newton’s theories of gravity increased understanding of the movement of planets.</h2>

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3 years ago
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How do I calculate initial speed by using the slope of a graph? The graph shows the relationship between S {(sin2ϴ)/g} and the a
Orlov [11]
The formula for slope is y=mx+b
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3 years ago
The y-component of the force F which a person exerts on the handle of the box wrench is known to be 70 lb. Determine the x-compo
Yuri [45]

Answer:

<em>Fx = 121.24lb</em>

<em>F = 140lb</em>

Explanation:

Since we are not given the angles subtended by the force, we can assume it to be 30 degrees.

The y component of the force expressed by the formula:

Fy = Fsintheta

Given the y-component of the force F to bee 70lb

70lb =  Fsintheta

Get magnitude of the force

F = 70/sin theta

F = 70/sin 30

F = 70/0.5

F = 140lb

Get the x-component of the force

Fx = Fcos theta

Fx = 140cos 30

Fx = 140(0.8660)

Fx = 1,212.4lb

<em>Hence the  x-component of the force sis 121.24lb</em>

<em></em>

<em>Note that the angle used was assumed. Other values can as well be used</em>

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