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BigorU [14]
3 years ago
5

(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500-μC charge and flies due west at a spee

d of 660 m/s over the Earth’s magnetic south pole (near Earth's geographic north pole), where the 8.00×10−5 -T magnetic field points straight down. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect
Physics
1 answer:
Akimi4 [234]3 years ago
7 0

Answer:

(a) Magnitude of Magnetic force on jet will be 2.64 ×10^{-8} N and direction will be towards South.

(b) The value obtained in part (a) will have negligible effect.

Explanation:

(a) The magnetic force acting on a moving charge is given by :-

<em />\vec{F}<em> = q ( </em>\vec{v} \times \vec{B}<em>)</em>

So, magnitude of Force will be:-

F = 0.5 × 10^{-6} × ( 660 × 8 × 10^{-5} ) × sin (90⁰)

  = 2.64 ×10^{-8} N.

And direction can be found out using Right Hand Thumb Rule.

It comes out to be towards South.

(b)  The gravitational force acting on the jet is massive as the mass of jet is very large. Compared to that, the value obtained above is negligible.

If the jet can overcome gravitational force and fly, the magnetic force will have negligible effect.        

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Elanso [62]

Answer:

Part a)

A = 0.066 m

Part b)

maximum speed = 0.58 m/s

Explanation:

As we know that angular frequency of spring block system is given as

\omega = \sqrt{\frac{k}{m}}

here we know

m = 3.5 kg

k = 270 N/m

now we have

\omega = \sqrt{\frac{270}{3.5}}

\omega = 8.78 rad/s

Part a)

Speed of SHM at distance x = 0.020 m from its equilibrium position is given as

v = \omega \sqrt{A^2 - x^2}

0.55 = 8.78 \sqrt{A^2 - 0.020^2}

A = 0.066 m

Part b)

Maximum speed of SHM at its mean position is given as

v_{max} = A\omega

v_{max} = 0.066(8.78) = 0.58 m/s

4 0
3 years ago
A battery charger is connected to a dead battery and delivers a current of 3.5 a for 4 hours, keeping the voltage across the bat
oksano4ka [1.4K]
The power delivered is equal to the product between the voltage V and the current I:
P=VI=(16 V)(3.5 A)=56 W

This power is delivered for a total time of t=4h=4 \cdot 3600 s = 14400 s, so the total energy delivered to the battery is
E=Pt = (56 W)(14400 s)=806400 J=806.4 kJ
5 0
3 years ago
The distance between 4 nodes (3 sections, 2 sections= wavelength) is 15.0cm. The frequency of the source is 10Hz. What's the spe
Natalija [7]

Answer:

the speed of the waves is 150 cm/s

Explanation:

Given;

frequency of the wave, f = 10 Hz = 10

distance between 4 nodes, L = 15.0 cm

The wavelength (λ) of the wave is calculated as follows;

Node to Node = λ/2

L = 2(Node to Node) = (4 Nodes) = 2 (λ/2) = λ

Thus, λ = L = 15.0 cm

The speed (v) of the wave is calculated as follows;

v = fλ

v =  10 Hz   x  15.0 cm

v = 150 cm/s

Therefore, the speed of the waves is 150 cm/s

7 0
2 years ago
Kepler’s third law can be used to derive the relation between the orbital period, P (measured in days), and the semimajor axis,
NikAS [45]
Kepler's 3rd law is given as
P² = kA³
where
P = period, days
A = semimajor axis, AU
k = constant

Given:
P = 687 days
A = 1.52 AU

Therefore
k = P²/A³ = 687²/1.52³ = 1.3439 x 10⁵ days²/AU³

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8 0
3 years ago
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Which of the following statements about psychodynamic perspective is not true?
Free_Kalibri [48]
There are NO true statements on that list of choices.
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