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klasskru [66]
2 years ago
8

The ability of a telescope to separate two closely spaced stars is called _____.

Physics
1 answer:
larisa [96]2 years ago
3 0

The ability of a telescope to separate two closely spaced stars is called (angular) resolution.

What is a telescope ?

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky. The original telescopes employed lenses, which are simply curved pieces of clear glass, to focus light.

The capacity of a telescope to distinguish two point sources into distinct pictures is known as resolution. The resolving power is constrained by diffraction effects in ideal circumstances, such as above the atmosphere where there is no turbulence (seeing).

to learn more about telescope click on the link below:

brainly.com/question/24999277

#SPJ4

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In an arcade game a 0.099 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releas
Sonja [21]

Answer:

The speed of disk is 1.98 \frac{m}{s}

Explanation:

Given:

Mass of m = 0.099 kg

Spring constant k = 244 \frac{N}{m}

Compression of spring x = 4 \times 10^{-2} m

From energy conservation theorem,

Spring potential energy converted into kinetic energy,

   \frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}

  v = \sqrt{\frac{k x^{2} }{m} }

  v = \sqrt{\frac{244 \times 16 \times 10^{-4} }{0.099} }

  v = 1.98 \frac{m}{s}

Therefore, the speed of disk is 1.98 \frac{m}{s}

8 0
3 years ago
A 1423-kg car is moving along a level highway with a speed of 26.4 m/s. The driver takes the foot off the accelerator and the ca
Leona [35]

Answer:

Final speed, v = 28.81 m/s

Explanation:

Given that,

Mass of the car, m = 1423 kg

Initial speed of the car, u = 26.4 m/s

Force experience by the car, F = 901 N

Distance, d = 106 m

To find,

The speed of the car after traveling this distance.

Solution,

The force experienced by a car is equal to the product of mass and acceleration.

F=ma

a=\dfrac{F}{m}

a=\dfrac{901}{1423}

a=0.63\ m/s^2

Let v is the final speed of the car. Using third equation of motion to find it as :

v^2-u^2=2ad

v^2=2ad+u^2

v^2=2\times 0.63\times 106+(26.4)^2

v = 28.81 m/s

So, the final speed of the car is 28.81 m/s.

5 0
4 years ago
A rock dropped on the moon will increase its speed from 0m/s to 8.15 m/s in 5 seconds what is the acceleration of the rock
sergejj [24]

speed  Δv     =  v₂ =  8.15ms⁻¹

                     v₁ = 0ms⁻¹

time  =t = 5s

acceleration  =  a = speed / time taken

                          a =    Δv / Δt           ( as Δv = v₂ - v₁)

                          a  =   8.15ms⁻¹  /  5 s

                            a  = 1.6ms⁻²

                               

3 0
4 years ago
BRainliest if correct
kolbaska11 [484]

Answer:

C.

hope this helps

have a good day :)

Explanation:

4 0
3 years ago
Read 2 more answers
How are you progressing towards the goals you set for yourself? What do you need to keep on track?
Pepsi [2]

Answer:

Set small goals for yourself

Explanation:

the goals you start with do not need to be huge, break down the goal Into smaller tasks. this is a system called metronome growth system.

7 0
3 years ago
Read 2 more answers
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