Spinning a marshmallow over a fire is effective maybe if you hang it over the fire and heat it up equally on each side
I assume the 100 N force is a pulling force directed up the incline.
The net forces on the block acting parallel and perpendicular to the incline are
∑ F[para] = 100 N - F[friction] = 0
∑ F[perp] = F[normal] - mg cos(30°) = 0
The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.
Then
F[friction] = 100 N
F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N
If µ is the coefficient of static friction, then
F[friction] = µ F[normal]
⇒ µ = (100 N) / (84.9 N) ≈ 1.2
Answer:
F = 2389.603 N
Explanation:
Given:
Mass m = 1,369.4 kg
Initial velocity u = 28.9 m/s
Final velocity v = 20 m/s
Time t = 5.1 s
Find:
Net force
Computation:
a = (v - u)/t
a = (20 - 28.9)/5.1
a = -1.745 m/s²
F = ma
F = (1369.4)(1.745)
F = 2389.603 N
Yes, eg., when 2 bodies move in opposite directions
, the relative velocity of each is greater than the individual velocity of either
Answer:
a
The direction of the wave propagation is the negative z -axis
b
The amplitude of electric and magnetic field are
,
respectively
Explanation:
According to right hand rule, your finger (direction of electric field) would be pointing in the positive x-axis i.e towards your right let your palms be face toward the direction of the magnetic field i.e negative y-axis (toward the ground ) Then anywhere your thumb stretched out is facing is the direction of propagation of the wave here in this case is the negative z -axis
The Intensity of the wave is mathematically represented as

Given that 
Making
the subject we have

Substituting values as given on the question
![E_{rms} = \sqrt{\frac{7.43 *10^7[\frac{W}{m^2} ]}{0.5 * 3.08*10^8 *8.85*10^{-12}} }](https://tex.z-dn.net/?f=E_%7Brms%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B7.43%20%2A10%5E7%5B%5Cfrac%7BW%7D%7Bm%5E2%7D%20%5D%7D%7B0.5%20%2A%203.08%2A10%5E8%20%2A8.85%2A10%5E%7B-12%7D%7D%20%7D)

The amplitude of the electric field is mathematically represented as



The amplitude of the magnetic field is mathematically represented as

Substituting value

