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frosja888 [35]
3 years ago
7

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

Physics
1 answer:
Kitty [74]3 years ago
4 0
To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²
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=>  \  \ \ \ \ \ \ \  T =\frac{29.4}{2sin(8.130)}

=>  \  \ \ \ \ \ \ \  T = 103.96N

             

                 

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