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frosja888 [35]
3 years ago
7

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

Physics
1 answer:
Kitty [74]3 years ago
4 0
To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²
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\sum F = 0

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Here,

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g =Gravitational energy

The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore

\rho_w V_{displaced} g = mg

Remember the expression for which you can determine the relationship between mass, volume and density, in which

\rho = \frac{m}{V} \rightarrow m = V\rho

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Since the displaced volume of water is 0.429 we will have to

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7 0
3 years ago
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Sergeeva-Olga [200]

Answer:

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Uses of thrust reversal in practice:

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