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2 years ago

7

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

1 answer:

Kitty [74]2 years ago

4 0

To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²

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Transverse waves are generally stronger than longitudinal waves. True or False ?

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False
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3 years ago

Determine the weight in newtons of a woman whose weight in pounds is 157. Also, find her mass in slugs and in kilograms. Determi

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Answer:

Weight of the woman in Newton

$x = 698.6 \ N$

Mass of the woman in slug

$Mass = 4.86 \ slug$

Mass of the woman in kg

$Mass = 16 \ kg$

My weight in Newton

$W = 784 \ N$

Explanation:

From the question we are told that

The weight of the woman in pounds is $W = 157 \ lb$

Converting to Newton

1 N = 0.22472 lb

x N = 157

=> $x = \frac{157 * 1}{0.22472}$

=> $x = 698.6 \ N$

Obtaining the mass in slug

$Mass = \frac{W}{g}$

Here $g = 32.2 ft/s^2$

So

$Mass = \frac{157 }{32.2}$

$Mass = 4.86 \ slug$

Obtaining the mass in kilogram

$Mass = \frac{W}{g}$

Here $g = 9.8 \ m/s$

So

$Mass = \frac{157 }{9.8}$

$Mass = 16 \ kg$

Generally weight is mathematically represented as

$W = m * g$

Given that my mass is 80 kg then my weight is

$W = 80 *9.8$

$W = 784 \ N$

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2 years ago

What is the S.I. unit of drift velocity and electron mobility?

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3 years ago

If a non-human civilization were to develop on Saturn's largest moon, Titan, its scientists might well develop a temperature sca

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Explanation:

Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:

$\°C +273.15=K$

This means the absolute zero point of the Kelvin scale is $0 K=-273.15 \°C$

Keeping this in mind, we have the freezing point and boling point of Methane as:

Freezing point: $0 \°M=-182.6 \°C=90.55 K$

Boiling point: $100 \°M=-155.2 \°C=117.95 K$

According to this, there is a linear relation between the methane scale ( $\°M$ ) and the Kelvin scale in the form:

$T=a+bt_{M}$ (1)

Where:

$T$ is the temperature in Kelvin

$t_{M}$ is the temperature in degrees Methane

Firstly, we need to find the value of $a$ and $b$ with the two given points ( $90.55 K$ and $117.95 K$ ):

When $T=90.55$ and $t_{M}=0$ :

$90.55=a+b(0)$

$a=90.55$ (2)

When $T=117.95$ and $t_{M}=100$ :

$117.95=90.55+b(100)$

$b=0.274$ (3)

Now we have the linear equation:

$T=90.55+0.274t_{M}$ (4)

Isolating $t_{M}$ :

$t_{M}=\frac{T-90.55}{0.274}$ (5)

Evaluating for $T=0 K$ :

$t_{M}=\frac{0-90.55}{0.274}$ (6)

Finally:

$t_{M}=-330.47 \°M$

This means $0 K=-330.47 \°M$

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2 years ago