1. A train engine pulls the boxcars. What are the horizontal forces present?(1 point)
1 answer:
Force is the influence that is capable of bringing about motion
The correct options are;
1. C. The pull of the engine, friction force
2. A. Weight, push of the tracks against the wheel
3. D. The astronaut weighs the most on Earth and least on the Moon
4. Please see attached drawing for example
5. Please see attached drawing for example
6. The data points will fall along a line this that as the force increases, the acceleration increases
Reason:
1. The horizontal forces are the forces acting along the horizontal x-axis, therefore;
A train engine pulling a boxcar what horizontal forces are;
C. The pull of the engine, friction force
2. The vertical forces are the forces acting an the direction of the y-axis of a graph
The vertical forces present when a train pulls a boxcar are;
A. Weight, push of the tracks against the wheel
3. The weight of an astronaut, W = mass × Gravity
- Therefore, the weight increases with increasing acceleration due to gravity
Therefore, the least weight is on the moon, where acceleration due to gravity is 1.6 m/s², and most on Earth where the acceleration due to gravity is approximately 9.81 m/s²
- The correct option is D. The astronaut weighs the most on Earth and least on the Moon
4. The magnitude of the downward force is the sum of the vertical forces acting downwards
5. The net force is given by the vector sum of the forces
6. According to Newton's second law, Force, F = Mass, m × Acceleration, a
- Therefore, where the students conduct the experiments rightly, we have that the data points will fall along a line this that as the force increases, the acceleration increases
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Answer:
Explanation:
(A)
The string has set of normal modes and the string is oscillating in one of its modes.
The resonant frequencies of a physical object depend on its material, structure and boundary conditions.
The free motion described by the normal modes take place at the fixed frequencies and these frequencies is called resonant frequencies.
Given below are the incorrect options about the wave in the string.
• The wave is travelling in the +x direction
• The wave is travelling in the -x direction
• The wave will satisfy the given boundary conditions for any arbitrary wavelength
• The wave does not satisfy the boundary conditions
Here, the string of length L held fixed at both ends, located at x=0 and x=L
The key constraint with normal modes is that there are two spatial boundary conditions,
and
.The spring is fixed at its two ends.
The correct options about the wave in the string is
• The wavelength can have only certain specific values if the boundary conditions are to be satisfied.
(B)
The key factors producing the normal mode is that there are two spatial boundary conditions, and
, that are satisfied only for particular value of
.
Given below are the incorrect options about the wave in the string.
• must be chosen so that the wave fits exactly o the string.
• Any one of or
or
can be chosen to make the solution a normal mode.
Hence, the correct option is that the system can resonate at only certain resonance frequencies and the wavelength
must be such that
(C)
Expression for the wavelength of the various normal modes for a string is,
(1)
When , this is the longest wavelength mode.
Substitute 1 for n in equation (1).
When , this is the second longest wavelength mode.
Substitute 2 for n in equation (1).
When , this is the third longest wavelength mode.
Substitute 3 for n in equation (1).
Therefore, the three longest wavelengths are ,
and
.
(D)
Expression for the frequency of the various normal modes for a string is,
For the case of frequency of the normal mode the above equation becomes.
Here, is the frequency of the
normal mode, v is wave speed, and
is the wavelength of
normal mode.
Therefore, the frequency of normal mode is
.
Answer:
The average velocity is 50 km/h south
Explanation:
The average velocity of an object is its total displacement divided by
the total time taken.
That means it is the rate at which an object changes its position from
one place to another.
Average velocity is a vector quantity.
The SI unit is meters per second.
A bicycle that starts 100 km south and is 120 km south of town after
0.4 hour.
The displacement = 120 - 100 = 20 km south
The time = 0.4 hour
The average velocity = , where D is the displacement
and t is the time
The average velocity of the bicycle = km/h
<em>The average velocity is 50 km/h south</em>
If you want it in meter per second, change the kilometer to meter
and change the hour to seconds
1 km = 1000 m
1 hour = 60 × 60 = 3600 seconds
The average velocity of the bicycle = m/s south