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Arada [10]
2 years ago
15

1. A train engine pulls the boxcars. What are the horizontal forces present?(1 point)

Physics
1 answer:
NikAS [45]2 years ago
5 0

Force is the influence that is capable of bringing about motion

The correct options are;

1. C. The pull of the engine, friction force

2. A. Weight, push of the tracks against the wheel

3. D. The astronaut weighs the most on Earth and least on the Moon

4. Please see attached drawing for example

5. Please see attached drawing for example

6. The data points will fall along a line this that as the force increases, the acceleration increases

Reason:

1. The horizontal forces are the forces acting along the horizontal x-axis, therefore;

A train engine pulling a boxcar what horizontal forces are;

C. The pull of the engine, friction force

2. The vertical forces are the forces acting an  the direction of the y-axis of a graph

The vertical forces present when a train pulls a boxcar are;

A. Weight, push of the tracks against the wheel

3. The weight of an astronaut, W = mass × Gravity

  • Therefore, the weight increases with increasing acceleration due to gravity

Therefore, the least weight is on the moon, where acceleration due to gravity is 1.6 m/s², and most on Earth where the acceleration due to gravity is approximately 9.81 m/s²

  • The correct option is D. The astronaut weighs the most on Earth and least on the Moon

4. The magnitude of the downward force is the sum of the vertical forces acting downwards

5. The net force is given by the vector sum of the forces

6. According to Newton's second law, Force, F = Mass, m × Acceleration, a

  • Therefore, where the students conduct the experiments rightly, we have that the data points will fall along a line this that as the force increases, the acceleration increases

Learn more here;;

brainly.com/question/19657850

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<span>Electric field repulsive for objects of like charge and attractive for opposite type of charges and for a magnet you can say that like poles repel and unlike attracts so D makes sense</span>
3 0
3 years ago
2. A student drives 7.8-km trip to school and averages a speed of
Alekssandra [29.7K]

Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

We know the distance to school is 7.8 Km = 7,800 m. The student makes his way home over the same distance, thus the total distance is

x=2*7,800 m=15,600 m

The first trip to school was done at an average speed of v1=32.6 m/s. Knowing the distance and speed, we can calculate the time:

\displaystyle t1=\frac{x1}{v1}=\frac{7,800}{32.6}=239.26\ sec

The second trip back home was done at an average speed of v2=36.8 m/s. Let's calculate the second time:

\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

The total time is:

t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

\boxed{\displaystyle V=34.57\ m/s}

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<span>- (6666.7)t = 0 - (.01)(400) </span>

<span>t = .0006 s </span>

<span>the bullets acceleration is </span>

<span>a = - F/m = - 666667 m/s2 </span>

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