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sergeinik [125]
2 years ago
8

A parachute on a racing dragster opens and changes the speed of the car from 85 m/s to 45 m/s in a period of 4.5 seconds. What i

s the acceleration of the dragster?
please help me work it out, please don't give just the answer
Physics
1 answer:
Alex Ar [27]2 years ago
6 0

The acceleration of the dragster is 8.89 m/s².

To find the acceleration, the given values are,

V₀ = 85 m/s

V = 45 m/s

<h3>What is acceleration?</h3>
  • Acceleration is a rate of change of velocity with respect to time with respect to direction and speed.
  • Acceleration formula can be written as,

         \overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}`

a = acceleration

v = final velocity

v₀= starting velocity

t  =  time

  • Acceleration is a vector quantity.
  • The unit of acceleration is m/s².

Substituting the given values in the formula,

    a = (V-Vo)/time

       = (45-85m/s)/4.5 s.

    a = 8.89m/s².

Thus, the acceleration a of the dragster is 8.89 m/s².

Learn more about acceleration,

brainly.com/question/8231525

#SPJ1

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Answer:

1) The temperature will be closer to water

2) T = 68.239°C

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2)

137(1.089)(T - 23.8) = 137(4.186)(79.8 - T)

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3)

137(1.089)(T - 23.8) = 225(4.186)(79.8 - T)

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⇒1091.043 T = 78710.4234

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4)

137(1.089)(T - 23.8) + 11.7(4.186)(T - 5.2)= 225(4.186)(79.8 - T)

⇒(149.193)(T - 23.8) + 48.9762(T - 5.2) = (941.85)(79.8 - T)

⇒149.193 T - 3550.7934  + 48.9762 T - 254.67624= 75159.63 - 941.85 T

⇒149.193 T +  941.85 T + 48.9762 T = 75159.63  + 3550.7934 + 254.67624

⇒1091.043 T + 48.9762 T = 78710.4234 + 254.67624

⇒1140.0192 T = 78965.09964

⇒ T = 69.266 °C

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