What property do liquids and gases share

A baseball bat changes the momentum of a ball with an impulse of 13.8 Nᐧs. What is the average force that the bat exerts on the

vladimir2022 [97]

Answer:

13800 N

Explanation:

Impulse is the product of average force and time expressed as I=Ft where I is the impulse which results into change in momentum, F is the average force and t is the time of impact. Making F the subject of formula then

$F=\frac {I}{t}$

Substituting I with 13.8 N.s and time, t witg 0.001 s then the average force is calculated as

$F=\frac {13.8 N.s}{0.001}=13800N$

Therefore, the average force is equivalent to 13800 N

4 0

3 years ago

Question 20 of 31

lbvjy [14]

Answer:

C: Valence electrons are transferred from a metal to a nonmetal

Explanation:

In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

hope this was helpful :)

5 0

3 years ago

Consider a single photon with a wavelength of lambda, a frequency of nu, and an energy of E. What is the wavelength, frequency,

BARSIC [14]

Answer: lambda $\lambda$ , nu $\nu$ , and 100E

Explanation:

The energy $E$ of a photon is given by:

$E=h\nu$ (1)

Where:

$h$ is the Planck constant

$nu$ is the frequency

On the other hand, we have an expression that relates the frequency of the photn with its wavelength $\lambda$ :

$nu=\frac{c}{\lambda}$ (2) where $c$ is the speed of light

Substituting (2) in (1):

$E=h\frac{c}{\lambda}$ (3) This is the energy for a single photon

For 100 photons, the energy is:

$100E=100(h\frac{c}{\lambda})=100h\nu$ (3)

Where the wavelength and the frequency of the light remains constant.

Therefore, the answer is:

$\lambda$ , $\nu$ , and 100E

5 0

3 years ago

A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab

maria [59]

Answer:

W = 0.678 rad/s

Explanation:

Using the conservation of energy:

$E_i =E_f$

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

$\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh$

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I = $\frac{2}{3}mR^2$