Question

What horizontal force p must a worker exert on the rope to position the 50-kg crate directly over the trailer?

Answer 1

The tension in the rope is

$T_{1}=W_{create} g$

T1=50×9.81

T1=490.5 N

And the rope is in vertical position

When a worker exert a horizontal force P on the rope, new tension is

$T_{2} =\sqrt{T1^{2} +P^{2} }$

$T_{2} =\sqrt{490.5}^{2}+P^{2}$

Since T1 is vertical component to the tension T2

$T_{1} =T_{2} cos \alpha$

$490.5^{2} /cos^{2} 14.036=490.5^{2} +P^{2}$

$P^{2} =490.5^{2} /cos^{2} 14.036 - 490.5^{2}$

P= 122.62 N

What is horizontal reaction force?

As long as no horizontal applied forces are present, the horizontal response force is zero. A single-support cantilever beam has a response force and reaction moment. The total applied forces on the beam are equal to the reaction force.

When the compression pressures are removed, the distortion may either be permanent or reversible. In the latter scenario, the deformation creates reaction forces that compete with the compression forces and may ultimately bring them into balance.

To learn more about horizontal reaction force, visit:

brainly.com/question/13014940

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