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Korvikt [17]
3 years ago
10

During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f

orm a neutron star. As the core shrinks, conservation of angular momentum says that
a. the core will spin faster.
b. the spin of the core does not change.
c. the core's rotational axis will precess rapidly, forming a pulsar.
d. the core will spin more slowly.
Physics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

v= speed of star

R= radius of star

i= initial

f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

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You can use the impulse momentum theorem and just subtract the two momenta.
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If you first worked out the force and integrated it over time the result is the same
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3 years ago
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A top is a toy that is made to spin on its pointed end by pulling on a string wrapped around the body of the top. The string has
AlladinOne [14]

Given Information:

Angular displacement = θ = 51 cm = 0.51  m

Radius = 1.8 cm = 0.018 m

Initial angular velocity = ω₁ = 0 m/s

Angular acceleration = α = 10 rad/s ²

Required Information:

Final angular velocity = ω₂ = ?

Answer:

Final angular velocity = ω₂ = 21.6 rad/s

Explanation:

We know from the equations of kinematics,

ω₂² = ω₁² + 2αθ

Where ω₁ is the initial angular velocity that is zero since the toy was initially at rest, α is angular acceleration and θ is angular displacement.

ω₂² = (0)² + 2αθ

ω₂² = 2αθ

ω₂ = √(2αθ)

We know that the relation between angular displacement and arc length is given by

s = rθ

θ = s/r

θ = 0.51/0.018

θ = 23.33 radians

finally, final angular velocity is

ω₂ = √(2αθ)

ω₂ = √(2*10*23.33)

ω₂ = 21.6 rad/s

Therefore, the top will be rotating at 21.6 rad/s when the string is completely unwound.

3 0
3 years ago
A pendulum at position A is released and swings through position B to position Con the other side.
zaharov [31]

Explanation:

Given the conditions A,B and C when the pendulum is released, at point A the initial velocity of the pendulum is zero(0), the potential energy stored is maximum(P.E= max),

the conditions can be summarized bellow

point A

initial velocity= 0

final velocity=0

P.E= Max

K.E= 0

point B

initial velocity= maximum

final velocity=maximum

P.E=K.E

point C

initial velocity= min

final velocity=min

P.E= 0

K.E= max

3 0
3 years ago
Free p o i n t s. hurry before admin deletes ;-;
blsea [12.9K]
The answer is 3+5+4 = 10+3 so then you have to add the number to the part of the equation and you will get the answer of five
4 0
2 years ago
If 2.2 lbs = 1.0 kg, and Megan Progress weighs 130 lbs, what is her weight in newtons?
Dafna11 [192]

Answer:

Force = 2802.8 Newton

Explanation:

Given the following data;

Mass = 130 lbs

But, 2.2 lbs = 1.0 kg

130 lbs to kg = 130 * 2.2 = 286 kg

Acceleration due to gravity = 9.8m/s²

To find the force in Newton;

Force = mass * acceleration due to gravity

Force = 286 * 9.8

Force = 2802.8 Newton

8 0
3 years ago
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