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suter [353]
3 years ago
9

A box has a weight of 120 lbs and the bottom of the box is 12 in2 . What is the pressure the box exerts on the floor?

Chemistry
1 answer:
denis23 [38]3 years ago
7 0
How can I help with this question?
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In this experiment you will create solutions with different ratios of ethanol and water. What is the mole fraction of ethanol wh
Andrej [43]

Answer:

The mole fraction of ethanol is 0.6. A 10 mL volumetric pipette must be used for to measure the 10 mL of ethanol. The vessel should be clean and purged.

Explanation:

For calculating mole fraction of ethanol, the amount of moles ethanol must be calculated. Using ethanol density (0.778 g/mL), 10 mL of ethanol equals to 7.89 g of ethanol and in turn 0.17 moles of ethanol. The same way for calculate the amount of water moles (ethanol density=0.997 g/mL). 2 mL of water correspond to 0.11. The total moles are: 0.17+0.11=0.28. Mole fraction alcohol is: 0.17/0.28=0.6

5 0
3 years ago
Removing one electron from an atom results in the formation of an Question 7 options: ion with a 1- charge. ion with a 7+ charge
olga nikolaevna [1]

I believe it is an ion with a 1+ charge. If you remove an electron from an atom it will have a positive charge. But if you add electrons it will be a negative charge. Hope I helped!

5 0
3 years ago
What is the name of this molecule? (will give BRAINLIEST)
mrs_skeptik [129]

Answer:

2 - Butyne

Explanation:

The name of the molecule with a carbon atoms arranged in a straight chain with a triple bond between the second and third carbons is 2 - Butyne.

2- Butyne is an alkyne with structural formula given below. Some of the properties of Butyne include it is a produced artificially, it is volatile and colorless in nature.

Hence, the given molecules described is 2 - Butyne.

6 0
3 years ago
100 POINTS!!! :0! What two things do all chemical reactions have in common (tick 2)? 1. They create new substances- the substanc
dusya [7]

Answer:

1 and 4

Explanation:

7 0
3 years ago
Read 2 more answers
Calculate the specific heat of the substance if 373 J is required to raise the temperature of a 312 gram sample by 25°C?
I am Lyosha [343]

Explanation:

Q = 373J

∆∅ = 25°C

m = 312g

c = x

Q = mc∆∅

373 = 312(x)(25)

373 = 7800x

x = 373/7800

x = 0.0478J/(g°C)

4 0
3 years ago
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