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liq [111]
4 years ago
9

Explain the advantages and disadvantages of using concentric circles in describing the solar system to an elementary school chil

d.
Physics
1 answer:
kramer4 years ago
7 0

Some advantages would be that it's easy to understand and imagine. However, it misinforms the child for the fact that the planets actually conscribe ellipses around the sun.
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Which statement best describes who the period and frequency of electromagnetic was change between gamma rays and microwaves?
nalin [4]

Answer : <em> The period increases and the frequency decreases</em>.

Explanation :    

Gamma rays are the rays having frequency( \nu ) greater than 10^{19}\ Hz and frequency of microwave lie between 300 MHz to 300 GHz.

Since, E=h\nu

So, as we move from gamma rays to microwaves the energy increases because frequency is increasing.

Also, Time period T=\dfrac{1}{\nu}

We can say that as the time period increases, frequency decreases.


6 0
3 years ago
Read 2 more answers
How do you find the volume of a rectangular brick?​
timurjin [86]

Answer:

Multiply the length, width and height of the brick to calculate its volume.

Explanation:

3 0
3 years ago
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A coil 4.20 cm radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
erma4kov [3.2K]

Explanation:

Given that,

Radius of the coil, r = 4.2 cm

Number of turns in the coil, N = 500

The magnetic field as a function of time is given by :

B=1.2\times 10^{-2}t+2.6\times 10^{-5}t^4

Resistance of the coil, R = 640 ohms

We need to find the magnitude of induced emf in the coil as a function of time. It is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=N\pi r^2\dfrac{-dB}{dt}\\\\\epsilon=N\pi r^2\times \dfrac{-d(1.2\times 10^{-2}t+2.6\times 10^{-5}t^4)}{dt}\\\\\epsilon=N\pi r^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=500\pi \times (4.2\times 10^{-2})^2\times (1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\\\\\epsilon=2.77(1.2\times 10^{-2}+10.4\times 10^{-5}t^3)\ V

Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
In the Boyle’s law experiment, what was used to increase the pressure on the air (gas)?
MA_775_DIABLO [31]

Answer:

Volume.

Explanation:

Boyle’s law experiment :

This is also known as Mariotte's law or in the other words it is also known as Boyle–Mariotte law.

This law tell us about the variation of gas pressure when the volume of the gas changes at the constant temperature.According to this law the abslute pressure is inversely proportional to the volume .

We can say that

P\alpha \dfrac{1}{V}

Where P=Pressure

V=Volume

PV = K

K=Constant

When volume decrease then the pressure of the gas will increase.

That is why the answer is "Volume".

8 0
3 years ago
A weightlifter deadlifts a 300 kg weight. If the weightlifter has a mass of 100 kg, what is the force acting on his legs?
sergeinik [125]
300 + 100 = 400

(Im not 100% sure of this answer)
3 0
3 years ago
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