Rubber. The other three are metals, and therefore good conductors.
The absolute pressure is given by the equation,

Here,
is absolute pressure,
is atmospheric pressure and
is vacuum pressure.
Therefore,

The gage pressure is given by the equation,
.
Thus,
.
In kn/m^2,
The absolute pressure,

The gage pressure,
.
In lbf/in2
The absolute pressure,

The gage pressure,

In psi,
The absolute pressure,
.
The gage pressure,

In mm Hg
The absolute pressure,

The gage pressure,

Answer:
Showing results for Two point charge q, separated by 1.5cm have change value of +2.0 and -4.0AND/C respectively what is the magnitude of the Electric force midway between them?
Search instead for Two point charge q, seperated by 1.5cm have change value of +2.0 and -4.0N/C respectively what is the magnitude of the Electric force midway between them?
Hold on lemme get the link for you
Explanation:
(10) Mass of a soccer player, m = 0.42 kg
Initial speed, u = 0
Final speed, v = 32.5 m/s
Time, t = 0.21 s
We need to find the force that sends soccer ball towards the goal.
Force, F = ma

So, 65 N of force soccer ball sends towards the goal.
(11) Mass of the satellite, m = 72,000 kg
Initial speed, u = 0 m/s
Final speed, v = 0.63 m/s
Time, t = 1296 s
We need to find the force is exerted by the rocket on the satellite.
Force, F = ma

So, 35 N of the force is exerted by the rocket on the satellite.
Hence, this is the required solution.