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Rudiy27
3 years ago
11

When are you most aware of your motion in a moving vehicle: when it is moving steadily in a straight line or when it is accelera

ting? If you were in a car that moved with absolutely constant velocity (no bumps at all), would you be aware of the motion?
(A) Accelerating. You would not be aware of the motion if you did not look outside the car.

(B) Accelerating. You would be aware of the motion because humans can sense speed.

(C) Moving steadily in a straight line. You would be aware of the motion because you can feel velocity even in a closed car.

(D) Moving steadily in a straight line. You would be aware of the motion because you can feel the speed.
Physics
1 answer:
Ghella [55]3 years ago
6 0

Answer:

Acceleration is percieved, not constant velocity.

Explanation:

You are most aware when the vehicle is accelerating. At constant velocity you would not be aware of the motion. Only if the system is accelerated the dynamics must be solved considering a pseudo-force (of inertial origin) acting.

It's because of this that:

(A) False. The acceleration can be detected from the inside of a closed car.

(B) False. You would be aware of the motion, but not because humans can sense speed but acceleration.

(C) False. Constant velocity cannot be felt in a closed car.

(D) False. Again, you can't feel constant speed.

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Explanation:

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3 years ago
How much power does a crane develop doing 60,000 J of work in<br> 5.00minutes?
larisa [96]

Answer: 200W

Explanation: P = W/T

60,000 / (5*60) = 200

4 0
2 years ago
Light of wavelength 530.00 nm is incident normally on a diffraction grating, and the first‑order maximum is observed to be 33.0∘
GarryVolchara [31]

Answer:

1028 slits/mm

Explanation:

We are given that

Wavelength of light, \lambda=530nm=530\times 10^{-9} m

1nm=10^{-9} m

\theta=33^{\circ}

n=1

We have to find the number of slits per mm are marked on the grating.

We know that

dsin\theta=n\lambda

Using the formula

dsin33^{\circ}=1\times 530\times 10^{-9}

d=\frac{530\times 10^{-9}}{sin33^{\circ}}

d=9.731\times 10^{-7} m

1m=10^{3}mm

d=9.731\times 10^{-7}\times 10^3mm

d=0.0009731mm

Number of slits=\frac{1}{d}

Number of slits=\frac{1}{0.0009731}/mm

Number of slits=1028/mm

Hence, 1028 slits/mm are marked on the grating.

8 0
3 years ago
Read 2 more answers
What is an example of frequency
emmasim [6.3K]

'Frequency' is a word that often confuses some people ... for no good reason.
It just means "frequent-ness" or "often-ness" ... how often something happens.

The SI unit of frequency is the Hertz (Hz).  Hz means 'per second'.
So  " 13 Hz "  means  13 per second.

Here are examples of frequency:

-- 780 kilohertz (on your AM radio dial)
-- 98.7 Megahertz (on your FM dial)
-- 5.8 Gigahertz
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6 0
3 years ago
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allsm [11]

Answer:

v = 0.33 [m/s]

Explanation:

We must remember that speed is defined as the relationship between the displacement in a given time. In this way, we can propose the following equation.

v=d/t

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v = velocity [m/s]

d = displacement = 40 [m]

t = 2 [min] = 120 [s]

Now replacing we have:

v=40/120\\v=0.33[m/s]

6 0
3 years ago
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