Function is p(x)=(x-4)^5(x^2-16)(x^2-5x+4)(x^3-64)
first factor into (x-r1)(x-r2)... form
p(x)=(x-4)^5(x-4)(x+4)(x-4)(x-1)(x-4)(x^2+4x+16)
group the like ones
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
multiplicity is how many times the root repeats in the function
for a root r₁, the root r₁ multiplicity 1 would be (x-r₁)^1, multility 2 would be (x-r₁)^2
so
p(x)=(x-4)^8(x+4)^1(x-1)^1(x^2+4x+16)
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
(x^2+4x+16) is not on the real plane, but the roots are -2+2i√3 and -2-2i√3, each multiplicity 1 (but don't count them because they aren't real
baseically
(x-4)^8 is the root 4, it has multiplicity 8
(x-(-4))^1 is the root -4 and has multiplicity 1
(x-1)^1 is the root 1 and has multiplity 1
Answer:
24.
Step-by-step explanation:
the diameter is twice the radius
Answer:
7.06 x 10^(-7) ft 3
Step-by-step explanation:
We have the formula to calculate the volume of an octagonal Pyraamid as following:
<em>+) Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
As given, the base of the pyramid is an octagon with area equal to 15mm2
=> Area of the base = 15 mm2
The height of the pyramid is the length of the line segment which is perpendicular to the base - which is the red line.
=> Height = 4mm
So we have:
<em>Volume of octagonal pyramid = 1/3 * Area of the base * Height</em>
<em>= 1/3 * 15 * 4 = 20 mm3</em>
<em />
As: 1 mm3 = 3.53 x 10^(-8) ft 3
=> 20 mm3 = 7.06x10^(-7) ft 3
So the volume of the pyramid is : 7.06 x 10^(-7) ft 3
I think it's suppose to go
6% is .06 divided by 12 which is .005 times the number of months so in this case 9 so 5,000 times .005 times 9 which is 225 so 5,000 plus an interest of 225 adds up to 5,225