Question

if angle a is congruent to itself by the reflexive property, which transformation could be used to prove δabc ~ δade by aa similarity postulate?

Answer 1

Option B) Translate triangle ABC so that point C lies on point E to confirm angle C ≈ angle E is the correct option to prove that ∆ABC is similar to ∆ADE by AA similarity.

AA similarity postulates state that the two triangles are similar if the two angles of one triangle are equal to the two angles of the other triangle.

Here we have been given that there are two triangles which are triangle ABC and triangle ADE. And angle A of triangle ABC is equal to the angle A of triangle ADE. For AA similarity we need to prove two angles are equal here we have proved one angle equal. Therefore we need to prove another angle equal.

We can see from the figure that BC||DE and from the adjacent angle property angle C and angle E will be equal

Thus in ∆ABC and ∆ADE

     angle A = angle A  (common angle)

    angle C = angle E (adjacent angle)

Thus by AA similarity ∆ABC is similar to ∆ADE. Hence Option B) is correct.

Learn more about AA similarity here : brainly.com/question/11543627

#SPJ4