Answer:
the activation energy is 65-30
35
Answer:
so the reaction rate increases by a factor 6.
Explanation:
For the given equation the reaction is first order with respect to both ester and sodium hydroxide
So we can say that the rate law is
![Rate(initial)=K[NaOH][CH_{3}COOC_{2}H_{5}]](https://tex.z-dn.net/?f=Rate%28initial%29%3DK%5BNaOH%5D%5BCH_%7B3%7DCOOC_%7B2%7DH_%7B5%7D%5D)
now as per given conditions the concentration of ester is increased by half it means that the new concentration is 1.5 times of old concentration
The concentration of NaOH is quadrupled means the new concentration is 4 times of old concentration.
The new rate law is
![Rate(final)=K[1.5XNaOH][4XCH_{3}COOC_{2}H_{5}]](https://tex.z-dn.net/?f=Rate%28final%29%3DK%5B1.5XNaOH%5D%5B4XCH_%7B3%7DCOOC_%7B2%7DH_%7B5%7D%5D)
the final rate = 6 X initial rate
so the reaction rate increases by a factor 6.
Answer:
NaBr
Explanation:
When AgBr is dissolved in water, the following equilibrium is set up in solution;
AgBr(s)⇄Ag^+(aq) + Br^- (aq)
If we dissolve NaBr in the water, a common ion (Br^-) is now introduced into the system. This increases the concentration of Br^- and favours the reverse reaction hence more AgBr is precipitated. This is known as common ion effect.
Answer:
23.14 L
Explanation:
P1(V1)=P2(V2)
98kPa(v1)=(235kPa)(9.65L)
V1=23.14 L
Can cause a chemacal reaction
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