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maw [93]
2 years ago
10

the atomic mass of magnesium is 24 daltons and the atomic number is 12. a. how many electrons does an electrically neutral magne

sium atom have? b. how will the atomic mass of a magnesium atom be affected if the nucleus undergoes decay and loses a neutron? what is the term for this form of magnesium?
Chemistry
1 answer:
vekshin12 years ago
3 0

Atomic Mass will be 23 the new magnesium formed will be its isotope of magnesium.

We know that,

In stable condition

Number of electrons = Number of protons

Atomic number represents number of proton .

So, here number of proton is 12

Therefore, number of electron is 12

We know that -

Atomic mass = number of protons +Number of neutron

So if magnesium loses one neutron i.e. new number of neutron is 11

then its atomic mass changes.

New atomic mass will be

Atomic mass = 12 + 11

Atomic mass = 23

This new element with atomic mass 23 and atomic number 12 is the isotope of magnesium.

To know more about isotopes

brainly.com/question/11291241

#SPJ4

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Answer:

1.) 3

2.) 60 CM

Explanation:

1. Density=\frac{MASS}{VOLUME}= \frac{75}{25}

2. Length*Width*Height=3*10*2

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3 years ago
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A particular power source creates electricity through the use of giant magnets that are rotated to create a flow of electrons. T
Sloan [31]
From the electric generator to electric outlets in homes
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Bilangan oksidasi vanadium paling tinggi terdapat dalam senyawa..
emmasim [6.3K]
The answer is (b). As, vanadium is attached to five fluoride atoms, each flouride containing -1 oxidation state, hence five fluoride contains -5, to neutralize, vanadium should have +5 oxidation state.

8 0
3 years ago
What is the molarity of aqueous lithium bromide if 25.0 mL of LiBr reacts with 10.0 mL of 0.250 M Pb(NO 3) 2
bixtya [17]

The molarity of aqueous lithium bromide, LiBr solution is 0.2 M

We'll begin by calculating the number of mole of Pb(NO₃)₂ in the solution.

  • Volume = 10 mL = 10 / 1000 = 0.01 L
  • Molarity of Pb(NO₃)₂ = 0.250 M
  • Mole of Pb(NO₃)₂ =?

Mole = Molarity x Volume

Mole of Pb(NO₃)₂ = 0.25 × 0.01

Mole of Pb(NO₃)₂ = 0.0025 mole

Next, we shall determine the mole of LiBr required to react with 0.0025 mole of Pb(NO₃)₂

Pb(NO₃)₂ + 2LiBr —> PbBr₂ + 2LiNO₃

From the balanced equation above,

1 mole of Pb(NO₃)₂ reacted with 2 mole of LiBr.

Therefore,

0.0025 mole of Pb(NO₃)₂ will react with = 2 × 0.0025 = 0.005 mole of LiBr

Finally, we shall determine the molarity of the LiBr solution

  • Mole = 0.005 mole
  • Volume = 25 mL = 25 / 1000 = 0.025 L
  • Molarity of LiBr =?

Molarity = mole / Volume

Molarity of LiBr = 0.005 / 0.025

Molarity of LiBr = 0.2 M

Learn more about molarity: brainly.com/question/10103895

3 0
2 years ago
EDTA EDTA is a hexaprotic system with the p K a pKa values: p K a1 = 0.00 pKa1=0.00 , p K a2 = 1.50 pKa2=1.50 , p K a3 = 2.00 pK
mihalych1998 [28]

Answer:

Check the explanation

Explanation:

When,

pH = -log[H+] = 3.30

[H+] = 5.0 X 10^{-4} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^{-11}

alpha[Y^-4] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.56 X 10^{-20} + 3.12 X 10^{-17} + 2 X 10^{-15} + 4 X 10^{-14} + 1.6 X 10^{-13} + 2.34 X 10^{-16} + 2 X 10^{-23}

= 2.02 X 10^{-13}

When,

pH = -log[H+] = 10.15

[H+] = 7.08 X 10^{-11} M

Ka1 = 1 ; Ka2 = 0.0316 ; Ka3 = 0.01 ; Ka4 = 0.002 ; Ka5 = 7.4 X 10^{-7} ; Ka6 = 4.3 X 10^-11

alpha[Y^{-4}] = [H+]^6 + Ka1[H+]^5 + Ka1Ka2[H+]^4 + Ka1Ka2Ka3[H+]^3 + Ka1Ka2Ka3Ka4[H+]^2 + Ka1Ka2Ka3Ka4Ka5[H+] + Ka1Ka2Ka3Ka4Ka5Ka6

= 1.26 X 10^{-61} + 1.8 X 10^{-51} + 8.1 X 10^{-43} + 1.12 X 10^{-34} + 3.17 X 10^{-27} + 3.3 X 10^{-23} + 1.83 X 10^{-23}

= 5.12 X 10^{-23}

4 0
3 years ago
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