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zubka84 [21]
2 years ago
6

If there is a New Moon at midnight on October 1, when would the next New Moon occur?

Chemistry
1 answer:
irina1246 [14]2 years ago
8 0
Answer: C

Explanation: A lunar month is 29.53 earth days. Since an earth calendar as only integer days, it could be either 29 or 30 days later.
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Consider the structures of vinegar and triglyceride and draw in any bond dipoles that exist in the molecules above using a dipol
bagirrra123 [75]

Answer:

Given molecules are vinegar and triglycerides.

Explanation:

The dipole is a vector quantity and it is heading from less electronegative atom to more electronegative atom in a polar covalent bond.

The structures and the bond dipoles in the given molecules are shown below:

5 0
3 years ago
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

8 0
2 years ago
Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The
allsm [11]

<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 8.04 days

Putting values in above equation, we get:

k=\frac{0.693}{8.04days}=0.0862days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.0862days^{-1}

t = time taken for decay process = 39 days

[A_o] = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}

[A]=0.278g

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

3 0
2 years ago
How to Calculate the mass percent of silver in silver nitrate
kirza4 [7]

<span>Molar mass of AgNO3 = 169.8731 g/mol</span>

Convert grams Silver Nitrate to moles  or  moles Silver Nitrate to grams

Molecular weight calculation:
107.8682 + 14.0067 + 15.9994*3

6 0
3 years ago
How the moon surface is visible to an observer on earth
ehidna [41]

The moon surface is visible to an observer on earth due to the gravitational force that attracts the moon to the earth. The more massive the body is, the more the smaller body is attracted to the larger body. We can only see the side of the moon due to the speed at which the moon rotates.

3 0
3 years ago
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