Answer:
Given molecules are vinegar and triglycerides.
Explanation:
The dipole is a vector quantity and it is heading from less electronegative atom to more electronegative atom in a polar covalent bond.
The structures and the bond dipoles in the given molecules are shown below:
If the length of a string increases 2 times but the mass of the string remains constant, the original density will be multiplied by a factor mathematically given as
v=1.414 times
<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>
Generally, the equation for the volume is mathematically given as
v = sqt(TL/m)
Where
density = mass/length
Therefore


In conclusion,v ratio will give us
v=1.414 times
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<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:

where,
= half life of the reaction = 8.04 days
Putting values in above equation, we get:

Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = 39 days
= initial amount of the sample = 8.0 grams
[A] = amount left after decay process = ?
Putting values in above equation, we get:
![0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}](https://tex.z-dn.net/?f=0.0862%3D%5Cfrac%7B2.303%7D%7B39%7D%5Clog%5Cfrac%7B8.0%7D%7B%5BA%5D%7D)
![[A]=0.278g](https://tex.z-dn.net/?f=%5BA%5D%3D0.278g)
Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams
<span>Molar mass of AgNO3 = 169.8731 g/mol</span>
Convert grams Silver Nitrate to moles or moles Silver Nitrate to grams
Molecular weight calculation:
107.8682 + 14.0067 + 15.9994*3
The moon surface is
visible to an observer on earth due to the gravitational force that attracts the
moon to the earth. The more massive the body is, the more the smaller body is
attracted to the larger body. We can only see the side of the moon due to the
speed at which the moon rotates.