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Anarel [89]
3 years ago
7

A sealed container with liquid water in the bottom was left standing at a constant temperature until the air above the water sur

face became saturated with water vapor. The resulting pressure exerted by the water vapor is known as the ______ vapor pressure. The resulting vapor pressure value is unique to that particular temperature.
Chemistry
1 answer:
Julli [10]3 years ago
7 0

Answer:

Saturation.

Explanation:

Hello,

In this case, the statement is accounting for the saturation vapor pressure as it is the pressure of a vapor which is in equilibrium with its liquid, in other words it is the maximum exerted pressure possible by the vapor at a given temperature or just the maximum amount of the vapor, so there is neither no more vapor that could condense nor more liquid that could boil.

Best regards.

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In an aqueous solution at 25°C, if [H30+] = 3.3 * 10^4 M, then [OH-] is:
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Answer:

[OH-] = 3.0 x 10^-19 M

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[H3O+][OH-] = Kw

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The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
musickatia [10]

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

3 0
3 years ago
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