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Anarel [89]
3 years ago
7

A sealed container with liquid water in the bottom was left standing at a constant temperature until the air above the water sur

face became saturated with water vapor. The resulting pressure exerted by the water vapor is known as the ______ vapor pressure. The resulting vapor pressure value is unique to that particular temperature.
Chemistry
1 answer:
Julli [10]3 years ago
7 0

Answer:

Saturation.

Explanation:

Hello,

In this case, the statement is accounting for the saturation vapor pressure as it is the pressure of a vapor which is in equilibrium with its liquid, in other words it is the maximum exerted pressure possible by the vapor at a given temperature or just the maximum amount of the vapor, so there is neither no more vapor that could condense nor more liquid that could boil.

Best regards.

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2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)
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The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

Learn more about stoichiometry:

brainly.com/question/14735801

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3 attempts left Check my work Click in the answer box to activate the palette. Write the balanced chemical equation where liquid
mel-nik [20]

Answer:

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Explanation:

When a substance burns we talk about a combustion reaction. When combustion is complete the products are carbon dioxide and water, like in this case. The equation is:

C₄H₁₀(l) + O₂(g) ⇄ CO₂(g) + H₂O(g)

First, we balance the element with the largest stoichiometric coefficient (C).

C₄H₁₀(l) + O₂(g) ⇄ 4 CO₂(g) + H₂O(g)

Then, we balance H because it is in just 1 compound on each side.

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Since we want the smallest whole numbers, we multiply all coefficients by 2.

2 C₄H₁₀(l) + 13 O₂(g) ⇄ 8 CO₂(g) + 10 H₂O(g)

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